20
The first three is 3000 and the second three is worth 300.
Let F = father's age Let S = son's age F = 3S F - 5 = 4(S-5) F - 5 = 4S -20 F = 4S - 15 F = 3S 3S = 4S-15 S = 15, age of son
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
331/3 = 3,333.333... percent (the 3s can never end)
(3 + 3) / .3
(3+3) / .3
33/3 = 11
20
20 divided by 3 = 6 and 2/3
The first three is 3000 and the second three is worth 300.
4=4(3s) 4=12s s= 1/3
2,560
Aluminum can make three bonds without hybridization because it has three valence electrons in its 3s and 3p orbitals. Its electron configuration is 1s2 2s2 2p6 3s2 3p1.
Let F = father's age Let S = son's age F = 3S F - 5 = 4(S-5) F - 5 = 4S -20 F = 4S - 15 F = 3S 3S = 4S-15 S = 15, age of son
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3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s