(3!)!/(3!*3!) = 20, where n! = 1*2*...*n is n-factorial
Proof :
3! =1*2*3=6, (3!)!=6!=1*2*3*4*5*6=720, therefore : (3!)!/(3!*3!) = 720/6*6 =720/36 = 20
20
The first three is 3000 and the second three is worth 300.
Let F = father's age Let S = son's age F = 3S F - 5 = 4(S-5) F - 5 = 4S -20 F = 4S - 15 F = 3S 3S = 4S-15 S = 15, age of son
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
331/3 = 3,333.333... percent (the 3s can never end)
(3 + 3) / .3
(3+3) / .3
33/3 = 11
20
20 divided by 3 = 6 and 2/3
The first three is 3000 and the second three is worth 300.
4=4(3s) 4=12s s= 1/3
2,560
Let F = father's age Let S = son's age F = 3S F - 5 = 4(S-5) F - 5 = 4S -20 F = 4S - 15 F = 3S 3S = 4S-15 S = 15, age of son
Aluminum can make three bonds without hybridization because it has three valence electrons in its 3s and 3p orbitals. Its electron configuration is 1s2 2s2 2p6 3s2 3p1.
Yes, there are car chargers for CRV-3s for as low as $7.99 available. anonymous@oola.com
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s