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'x' can't represent an odd integer, simply because 'x' is not always odd.
If you can guarantee that 'x' is odd, then the previous odd number is (x-2),
and the next one is (x+2).
The smallest number that MUST be odd for ANY value of 'x' is (2x-1).
The smallest two consecutive odd integers for any value of 'x' are (2x-1) and (2x+1).
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You can use the same expressions to represent either consecutive odd or consecutive even integers?
Consecutive odd and even integers are both 2 apart. That is the reason we use the same denotation to represent them in an equation. x and x+2
The product of what two consecutive odd integers is 255?
15 x 17
If the sum of two consecutive even integers is 124 What are the integers?
No two consecutive EVEN integers sum to 124 since: Let x be the lowest of the two integers. Then the other integer is x+2 and x + (x+2) = 124 iff 2x = 122 iff x=61, an odd integer.
Find two consecutive integers such that the sum of the smaller and 3 times the larger is 330?
x + 3(x +1) = 330 4x = 327 which doesn't give an answer in integers. If question should read "consecutive ODD integers" the answer would be 81 and 83.
The sum of four consecutive odd integers is 200 find these integers?
Let the first integer be x. Since the integers are consecutive odds we know that the integers are x, x+2, x+4,and x+6. Since the sum of all of these is 200 we can set up the equation:4x+12 = 200. Solving we get x=47. Therefore the integers are 47, 49, 51, and 53.
What Four consecutive odd integers whose sum is -220?
Let x be the smallest of the consecutive odd integers. Since consecutive odd integers differ by 2, we havex + (x + 2) + (x + 4) + (x + 6) = -2204x + 12 = -220 (subtract 12 to both sides)4x = -232 (divide by 4 to both sides)x = -58Thus, the four consecutive odd integers whose sum is -220 are -58, -56, -54, and -52.
What is the three odd consecutive integers whose sum is 531?
There are no three odd consecutive integers because consecutive integers all have 1 between them, meaning at least one of them will be an even integer. ------------------- Let x, x+2, and x+4 be the three consecutive odd integers. We want x+(x+2)+(x+4) to equal 531. x+(x+2)+(x+4) = 531 3x+6=531 3x=531-6=525 x=525/3=175 Therefore, the three consecutive odd integers are 175, 177, and 179. A quick check shows that those three integers add up to 531.
You can use the same expressions to represent either consecutive odd or consecutive even integers?
Consecutive odd and even integers are both 2 apart. That is the reason we use the same denotation to represent them in an equation. x and x+2
The larger of two consecutive integers is represented by x plus 4 Which expression represents the smaller integer?
x+3 and x+4 would be consecutive integers.
What is the smallest of four consecutive odd integers whose sum is 968?
Let x be the 1st odd integer, then the next three odd integers are x+2, x+4, and x+6x+(x+2)+(x+4)+(x+6) = 9684x+12 = 9684x = 956x = 239so the 4 consecutive odd integers are 239, 241, 243, 245
Find two consecutive odd integers whose sum is 72?
Two consecutive odd integers are 'X' and 'X+2' . X + (X + 2) = 72 2X + 2 = 72 2X = 70 X = 35 X + 2 = 37
The product of what two consecutive odd integers is 255?
15 x 17
What is the difference between expressing consecutive even integers and consecutive odd integers algebraically?
There is no difference, only your outcome. The formula for both is x+2
3 consecutive odd integers that add up to negative 237?
240
What is the value of X when the sum of three consecutive odd integers is 84?
The three integers are 27, 28 and 29. Pick your own x...
Why can't x and x plus 1 represent two consecutive odd integers?
If x is odd, then x+1 is even. Try this out with a few numbers.
Twice the smallest of three consecutive odd integers is seven more than the largest find the integers?
Let's represent the three consecutive odd integers as ( 2n-1 ), ( 2n+1 ), and ( 2n+3 ), where ( n ) is an integer. According to the given information, twice the smallest integer ( 2(2n-1) ) is equal to seven more than the largest integer ( 2n+3 ). Setting up the equation, we have ( 4n-2 = 2n+3+7 ). Solving this equation gives us ( n = 6 ). Therefore, the three consecutive odd integers are 11, 13, and 15.
