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'x' can't represent an odd integer, simply because 'x' is not always odd.
If you can guarantee that 'x' is odd, then the previous odd number is (x-2),
and the next one is (x+2).

The smallest number that MUST be odd for ANY value of 'x' is (2x-1).

The smallest two consecutive odd integers for any value of 'x' are (2x-1) and (2x+1).

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Q: Consecutive odd integers can be represented by x and?
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Twice the smallest of three consecutive odd integers is seven more than the largest find the integers?

This equation works out to 2x = x + 11. This is because the three consecutive odd integers can be represented by x, x + 2, and x + 4. From the equation 2x - x = 11, so x = 11. Checking, 2 times 11 = 22 which is 7 more than 15. The three integers are 11, 13 and 15.


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There are no three odd consecutive integers because consecutive integers all have 1 between them, meaning at least one of them will be an even integer. ------------------- Let x, x+2, and x+4 be the three consecutive odd integers. We want x+(x+2)+(x+4) to equal 531. x+(x+2)+(x+4) = 531 3x+6=531 3x=531-6=525 x=525/3=175 Therefore, the three consecutive odd integers are 175, 177, and 179. A quick check shows that those three integers add up to 531.


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There is no difference, only your outcome. The formula for both is x+2


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If x is odd, then x+1 is even. Try this out with a few numbers.


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