r=y
I
Consider a sphere of radius r. Let the z-axis be the vertical axis and suppose the sphere's centre is at z = 0. [Thus the sphere goes from z = -r to z = r.] Suppose the volume of liquid in it is V. Then you need to sove 3V/pi = 3r2z - z3 + 3r3 - r3 = 3r2z - z3 + 2r3 for z. Then, the depth is z + r
it doesn't exist.
Yes. Suppose x divides y then there exist an integer p such that y = px. Suppose y divides z then there exist an integer q such that z = qy. Therefore z = q*px = qp*x Since p and q are integers then pq is an integer and therefore x divides z. That is to say: if x divides y and y divides z, then x divides z.
They are! Consider the identity map from Z to Q. They are not isomorphic, but there is a homomorphism between them.
first of all, what does ZZ stand for? Z x Z? or just Z (the integers)? I can answer better if I know the sets you are talking about.
No, the letter 'z' doesn't exist in the Mayan alphabet.
r=y
I
R. Z. Akberdin has written: 'Sterzhen' ekonomiki'
A functional dependency X->Y is transitive in R, if there exists an attribute Z in R, such that X-> Z, Z-> Y .
like this; A-Z-Z-A-R-O
z=rl +XL in a series circuit. if XL increases and r remains the same, z will increase. z is a complex number and the magnitude is z=(r^2 + (XL)^2)^.5. if the vector part of z increases z increases.
All Pokemon code: a b r l z b b lots of money: a b r r z z a a b b every pokeball: a a b z r l r a able to catch every 3rd and/or 2nd evolution Pokemon: a z a a b b r l ***DO NOT FOLLOW THIS. THIS IS A HOAX.***
z varies directly as the square of r So z = cr2 where c is the constant of variation. z = 24 when r = 4 ie 24 = c*42 so that c = 24/42 = 1.5 When z = 121.5, 121.5 = 1.5*r2 so that r2 = 121.5/1.5 = 81 so that r = -9 or +9
It's not a bijection in Z because it's not surjective. For example, f(x) = 3 has no solution in Z. In other words, you can't double an integer (Z) to get an odd number. It works in R because it's ok to have decimals.