if x>3 then
r=y
I
Consider a sphere of radius r. Let the z-axis be the vertical axis and suppose the sphere's centre is at z = 0. [Thus the sphere goes from z = -r to z = r.] Suppose the volume of liquid in it is V. Then you need to sove 3V/pi = 3r2z - z3 + 3r3 - r3 = 3r2z - z3 + 2r3 for z. Then, the depth is z + r
it doesn't exist.
Yes. Suppose x divides y then there exist an integer p such that y = px. Suppose y divides z then there exist an integer q such that z = qy. Therefore z = q*px = qp*x Since p and q are integers then pq is an integer and therefore x divides z. That is to say: if x divides y and y divides z, then x divides z.
They are! Consider the identity map from Z to Q. They are not isomorphic, but there is a homomorphism between them.
first of all, what does ZZ stand for? Z x Z? or just Z (the integers)? I can answer better if I know the sets you are talking about.
The function ( R(z) ) is differentiable in regions where it is complex differentiable, meaning it satisfies the Cauchy-Riemann equations. Typically, this applies to regions in the complex plane where the function is continuous and its partial derivatives exist. If ( R(z) ) is expressed in terms of real variables ( x ) and ( y ) (where ( z = x + iy )), it is differentiable at points where these conditions hold true. Thus, the specific answer depends on the form of ( R(z) ).
No, the letter 'z' doesn't exist in the Mayan alphabet.
To find all homomorphisms from (\mathbb{Z}{20}) to (\mathbb{Z}{6}), we first note that a homomorphism is completely determined by the image of a generator of (\mathbb{Z}{20}). The generator can be taken as (1), and the image must satisfy the property that the order of the image divides the order of the domain. The order of (\mathbb{Z}{20}) is 20, and the order of (\mathbb{Z}{6}) is 6. Thus, the image of (1) can be any element in (\mathbb{Z}{6}) that, when multiplied by 20, results in 0 in (\mathbb{Z}{6}). Since (20 \equiv 2 \mod 6), the possible images are restricted to elements of order dividing 2 in (\mathbb{Z}{6}), which are (0) and (3). Therefore, the homomorphisms are given by sending (1) to (0) (the trivial homomorphism) and sending (1) to (3).
r=y
I
R. Z. Akberdin has written: 'Sterzhen' ekonomiki'
A functional dependency X->Y is transitive in R, if there exists an attribute Z in R, such that X-> Z, Z-> Y .
like this; A-Z-Z-A-R-O
z=rl +XL in a series circuit. if XL increases and r remains the same, z will increase. z is a complex number and the magnitude is z=(r^2 + (XL)^2)^.5. if the vector part of z increases z increases.
All Pokemon code: a b r l z b b lots of money: a b r r z z a a b b every pokeball: a a b z r l r a able to catch every 3rd and/or 2nd evolution Pokemon: a z a a b b r l ***DO NOT FOLLOW THIS. THIS IS A HOAX.***