One point on a logarithmic graph is not sufficient to determine its parameters. It is, therefore, impossible to answer the question.
The horizontal asymptote is what happens when x really large. To start with get rid of all the variables except the ones with the biggest exponents. When x is really large, they are the only ones that will matter. If the remaining exponents are the same, then the ratio of those coefficients tell you where the horizontal asymptote is. For example if you have 2x3/3x3, then the ratio is 2/3 and the asymptote is f(x)=2/3 or y=2/3. If the exponent in the denominator is bigger, than y=0 is the horizontal asymptote. If the exponent in the numerator is bigger, than there is no horizontal asymptote.
A circle does not have an asymptote.
y=9
No if the denominators cancel each other out there is no asymptote
log5x
It is y = 0
The horizontal asymptote for y = 0 when the degree is greater than the denominator, resulting in the inability to do long division.
y = x / (x^2 + 2x + 1) The horizontal asymptote is y = 0
2x-2/x^2+3x-4
The domain is (-infinity, infinity) The range is (-3, infinity) and the asymptote is y = -3
y = 4(2x) is an exponential function. Domain: (-∞, ∞) Range: (0, ∞) Horizontal asymptote: x-axis or y = 0 The graph cuts the y-axis at (0, 4)
True
y = 1. When the degree of your numerator is the same with the degree of your denominator, then y = the ratio of the leading coefficients of the numerator and denominator is the horizontal asymptote.
2
One point on a logarithmic graph is not sufficient to determine its parameters. It is, therefore, impossible to answer the question.
no