3ab + 3ac + 2b2 + 2bc = 3a(b + c) + 2b(b + c) = (3a + 2b)(b + c)
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∙ 13y ago(3a - 2c)(b - d)
3a(b+c)+2b(b+c)
(a+b)(3b+1)
6
(3b - 1)(a - b)
12ab+3ab=15ab
(3b - 1)(a - b)
Factorizing 3ab + 3ac gives 3a (b + c).Factorizing is to express a number or expression as a product of factors.When factorizing always look for common factors. To factorize (3ab + 3ac) look for the highest factor between the two terms (3a). 3ab + 3ac = 3a (b + c)
3ab - a - 3b2 + b = -3b2 + 3ab + b - a = -3b(b - a) + 1(b - a) = (1 - 3b)(b - a)
It is: 3ab
3ab[35 - 4]
-2ab