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To factor the expression 3ab + 3ac + 2b^2 + 2bc, we first look for common factors among the terms. We can factor out a 3a from the first two terms, and a 2 from the last two terms. This gives us 3a(b + c) + 2(b^2 + bc). Next, we notice that we can factor out a b from the second term in the second parenthesis, giving us the final factored form: 3a(b + c) + 2b(b + c).

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2mo ago

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More answers

3ab + 3ac + 2b2 + 2bc = 3a(b + c) + 2b(b + c) = (3a + 2b)(b + c)

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Wiki User

15y ago
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Q: Factor 3ab plus 3ac plus 2b squared plus 2bc?
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