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What is 3 consecutive number when the product of the smaller two number is 37 less than the square of the largest number?
Wiki User
∙ 12y ago
Let the 3 consecutive number be represented by n, (n + 1) and (n + 2)
Then, n(n + 1) + 37 = (n + 2)2
n2 + n + 37 = n2 + 4n + 4
3n = 33
n = 11
The three numbers are 11, 12 and 13.
Wiki User
∙ 12y ago
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