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If the coordinate of A is x, and that of the midpoint of AB, M, is m then the distance AM is m-x so the distance AB = 2*(m-x) So the coordinate of B is x + 2*(m-x) = 2m-x For coordinates in more than one dimension, apply the above rule separately for each dimension.
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AB = 2 x 4 (8) C = 3 D = 5
a/b = 1 so a = b. Then a b = q implies that a = b = q/2 So ab = (q/2)*(q/2) = q2/4
If you mean end point A is (3, 5) and midpoint of line AB is (-2, 8) then end point B is (-7, 11)
If the coordinate of A is x, and that of the midpoint of AB, M, is m then the distance AM is m-x so the distance AB = 2*(m-x) So the coordinate of B is x + 2*(m-x) = 2m-x For coordinates in more than one dimension, apply the above rule separately for each dimension.
First find the length between the midsegment point and coordinate B. The difference between 0 and -3 is 3. Thus, half the line is 3. So, to get to A, we have to go 3 in the other direction. -3 and 3 more would make Coordinate A land on (-6,2)
8 1/3 = ab^-1, 1.8 =ab^2
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To find the coordinate for the midpoint, divide the differences in the X and Y positions by 2 and add to the lesser or subtract from the greater coordinate (the result has to be in between)X: from -9 to 5 is 14 units 14/2 =7-9 + 7 = -2Y: from 8 to -2 is 10 units 10/2 = 5-2 + 5 = 3The midpoint of AB is {-2;3}
Suppose the sides of the rectangle ABCD are not parallel to the axis. Then if A = (p,q) and B = (r, s) then by Pythagoras, |AB|2 = (p - r)2 + (q - s)2 from which AB can be calculated. Calculate BC in a similar fashion and then area = AB*BC If AB is parallel to an axis (say the x axis), then q = s so that q - s = 0 and |AB|2 simplifies to (p - r)2 + 02 so that |AB| = |p - r|
5.3 = 2x so x = 5.3/2 = 2.65
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AB = 2 x 4 (8) C = 3 D = 5
AB=2 so A=B/2 AC=CB/2. I guess that wasn't what you were looking for though. But that all that can be done with the information.
It can be but need not be.