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AB=2 so A=B/2

AC=CB/2. I guess that wasn't what you were looking for though. But that all that can be done with the information.

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Prove the mid-line theorem?

Let ABC be a triangle. Let D and E be the mid points of AB and AC respectively. Then the mid-line theorem states that DEBC and DE = BC/2.Extend DE beyond E to F such that DE = EF. Since AE = CE, triangles ADE and CEF are equal, making CFAB (or CFBD, which is the same) because, for the transversal AC, the alternating angles DAE and ECF are equal. Also,CF = AD = BD, such that BDFC is a parallelogram. It follows that BC = DF = 2·DE which is what we set out to prove.Conversely, let D be on AB, E on AC, DEBC and DE = BC/2. Prove that AD = DB and AE = CE.This is because the condition DEBC makes triangles ADE and ABC similar, with implied proportion,AB/AD = AC/AE = BC/DE = 2.It thus follows that AB is twice as long as AD so that D is the midpoint of AB; similarly, E is the midpoint of AC.


Asquare plus b square plus c square -ab -bc -ca equals 0 then show that a equals b equals c?

a^2 + b^2 + c^2 - ab - bc - ca = 0=> 2a^2 + 2b^2 + 2c^2 - 2ab - 2bc - 2ca = 0 => a^2 - 2ab + b^2 + b^2 - 2bc + c^2 + c^2 - 2ca + a^2 = 0 => (a - b)^2 + (b - c)^2 + (c - a)^2 = 0 Each term on the left hand side is a square and so it is non-negative. Since their sum is zero, each term must be zero. Therefore: a - b = 0 => a = b b - c = 0 => b = c.


What is circuit diagram for AB plus AB?

Is your question from digital electronics if yes than, AB + AB = AB ;and we can get this by using an 2 input AND gate(7408) where the two inputs are A & B and output will be AB. Only valid in digital domain.


What is the Definition of Factoring sum or difference of two cubes?

a^3 + b^3 = (a + b)(a^2 - ab + b^2) a^3 - b^3 = (a - b)(a^2 + ab + b^2)


Are absolute value and additive inverse equal why?

No. This is because absolute values are always positive. For example: |2|=2 absolute value Additive inverse means the opposite sign of that number so 2's additive inverse is -2. But sometimes if the number is -2 then the additive inverse equals the absolute value. therefore the answer is sometimes

Related Questions

If AB equals 5 and BC equals 8 then AC equals?

ac is 7 if b is 3 and a is 2 a nd c is 5


BC equals 1 What is the value of AB?

2


In triangle abc ab equals 2 and ac equals 11 what is angle c it is a right triangle?

It can be but need not be.


If ad equals x ab equals 2x-2 ae equals x plus 2 and ac equals 2x plus 1 find the value of x?

To find the value of ( x ), we can set up an equation using the given relationships. From the equations: ( ad = x ) ( ab = 2x - 2 ) ( ae = x + 2 ) ( ac = 2x + 1 ) Assuming these represent lengths that relate in a triangle or geometric figure, we can analyze them together. Matching the equations appropriately or checking for consistency often leads to the right value. Solving the system, we find that ( x = 2 ).


Point c is between the endpoints of segment ab if ac equals 2x minus 1 cb equals 3x and ab equals 9 solve for x and find ac and cb?

ac + cb = ab = 9 2x - 1 + 3x = 9 5x -1 = 9 So 5x = 10 Thereby x =2. Also ac = 3 and cb = 6


In this triangle side ac equals 1 side bc equals 1 and side ab equals 2 is triangle abc a right triangle?

no


In this triangle side ac equals 2 side bc equals 3 and side ab equals 4 is triangle abc a right triangle?

No siree


Ab equals 5.3 and CD equals 2X if ab and CD are congruent what is the value of x?

5.3 = 2x so x = 5.3/2 = 2.65


What are two segments that have the same measurement?

If 2 segments have the same length they are known as 'congruent segments' IE: segment AB=segment AC (or AB=AC) then AB @ AC (or AB is congruent to AC)


If AB is 34 and BC is 89nwhat is AC?

AC = sqrt(AB^2+BC^2) other wise known as a^2+b^2=c^2. Therefore AC is around 51.739


What is the answer to this ab - 2B plus ac -2C?

0


What is the formula to find AC?

To find the length of side AC in a triangle, you can use the Law of Cosines if you know the lengths of the other two sides (AB and BC) and the included angle (∠B). The formula is: [ AC^2 = AB^2 + BC^2 - 2 \times AB \times BC \times \cos(\angle B) ] After calculating AC², take the square root to find AC. If you have a right triangle, you can simply use the Pythagorean theorem: [ AC = \sqrt{AB^2 + BC^2} ] (assuming AC is the hypotenuse).