AC=5 AB=8 A=1 B=8 C=5 BC=40
Take a right angled triangle ABC with the right angle at B, so that AC is the hypotenuse. Let AC be 1 unit long. Using the angle CAB, the length of AC and the trigonometric ratios: sin = opposite/hypotenuse ⇒ sin CAB = AB/AC = AB/1 = AB cos = adjacent/hypotenuse ⇒ cos CAB = BC/AC = BC/1 = BC Using Pythagoras: AB2 + BC2 = AC2 ⇒ (sin CAB)2 + (cos CAB)2 = 12 ⇒ sin2θ + cos2θ = 1
a/b = 1 so a = b. Then a b = q implies that a = b = q/2 So ab = (q/2)*(q/2) = q2/4
the value of log (log4(log4x)))=1 then x=
If you mean endpoints of (-1, -3) and (11, -8) then the length works out as 13
no
\3
Do you mean F = abc + abc + ac + bc + abc' ? *x+x = x F = abc + ac + bc + abc' *Rearranging F = abc + abc' + ab + bc *Factoring out ab F = ab(c+c') + ab + bc *x+x' = 1 F = ab + ab + bc *x+x = x F = bc
8 1/3 = ab^-1, 1.8 =ab^2
4... if you plug it in, it works
AC=5 AB=8 A=1 B=8 C=5 BC=40
By use of the sine rule: sin A / BC = sin B / AC = sin C / AB Angles B and C are known, as is length AC, so: sin B / AC = sin C / AB AB = AC x sin C / sin B AB = 17cm x sin 24 / sin 95 ~= 6.94cm The ratios for the sine rule can also be given the other way up: BC / sin A = AC / sin B = AB / sin C (I learnt the rule the first way.) Further, if r is the radius of the triangle's circumcircle, then: sin A / BC = 1/2r or BC / sin A = 2r
yes it will definitely help you for BC next year.
Area = 0.5*AB*BC*sin(ABC) = 0.5*(2x+1)*(x+2)*0.5 = 3 So, (2x+1)*(x+2) = 12 2x2 + 5x + 2 = 12 2x2 + 5x - 10 = 0 x = 1.31 (to 3 sf)
Take a right angled triangle ABC with the right angle at B, so that AC is the hypotenuse. Let AC be 1 unit long. Using the angle CAB, the length of AC and the trigonometric ratios: sin = opposite/hypotenuse ⇒ sin CAB = AB/AC = AB/1 = AB cos = adjacent/hypotenuse ⇒ cos CAB = BC/AC = BC/1 = BC Using Pythagoras: AB2 + BC2 = AC2 ⇒ (sin CAB)2 + (cos CAB)2 = 12 ⇒ sin2θ + cos2θ = 1
(Coefficient of friction of plane ab) + 2(Coefficient of friction of plane bc) = 1 Coefficient of friction of plane ab = Coefficient of friction of plane bc = 1/3 = 0.33333......
NM equals 2x + 1, as stated in the question!