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Find the number of combinations that can be made from 10 objects taken 8 at a time?
Wiki User
ā 14y ago
If the position of the 8 objects within the group makes a difference, then
there are (10 x 9 x 8 x 7 x 6 x 5 x 4 x 3) = 1,814,400 possibilities.
If their sequence doesn't matter, and you only care which 8 objects are in the group,
then there are
(10 x 9 x 8 x 7 x 6 x 5 x 4 x 3) / (8 x 7 x 6 x 5 x 4 x 3 x 2) = 45 different groups.
Wiki User
ā 14y ago
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How many combinations can be made from 32 items taken 4 at a time and how do you do it?
Do a web search for "permutations and combinations" to find the how. I make it 35,960.
How do you find permutation?
If there are n objects and you have to choose r objects then the number of permutations is (n!)/((n-r)!). For circular permutations if you have n objects then the number of circular permutations is (n-1)!
How can you figure out combinations in math?
If you have N things and want to find the number of combinations of R things at a time then the formula is [(Factorial N)] / [(Factorial R) x (Factorial {N-R})]
How can you find the total number of 10 number combinations possible from digits 1-36?
1-36 are numbers, NOT digits. The number of combinations of 10 numbers out of 36 is 36*35*34*33*32*31*30*29*28*27/(10*9*8*7*6*5*4*3*2*1) which is 254,186,856
How many 5 digit combos in 30 numbers?
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
How can you Find the number of combinations of objects in a set?
The number of R-combinations in a set of N objects is C= N!/R!(N-R)! or the factorial of N divided by the factorial of R and the Factorial of N minus R. For example, the number of 3 combinations from a set of 4 objects is 4!/3!(4-3)! = 24/6x1= 4.
How do you find the number of combinations of 6 letters?
The number of combinations of 6 letters is 6! or 720.
How many combinations can be made from 32 items taken 4 at a time and how do you do it?
Do a web search for "permutations and combinations" to find the how. I make it 35,960.
How do you find all the combinations of a list?
To find the number of combinations possible for a set of objects, we need to use factorials (a shorthand way of writing n x n-1 x n-2 x ... x 1 e.g. 4! = 4 x 3 x 2 x 1). If you have a set of objects and you want to know how many different ways they can be lined up, simply find n!, the factorial of n where n is the number of objects. If there is a limit to the number of objects used, then find n!/(n-a)!, where n is the number of objects and n-a is n minus the number of objects you can use. For example, we have 10 objects but can only use 4 of them; in formula this looks like 10!/(10-4)! = 10!/6!. 10! is 10 x 9 x 8 x ... x 1 and 6! is 6 x 5 x ... x 1. This means that if we were to write out the factorials in full we would see that the 6! is cancelled out by part of the 10!, leaving just 10 x 9 x 8 x 7, which equals 5040 i.e. the number of combinations possible using only 4 objects from a set of 10.
What is the purpose of Pascal's triangle?
The Pascal's triangle is used partly to determine the coefficients of a binomial expression. It is also used to find the number of combinations taken n at a time of m things .
How many number combinations can you make using the numbers 9, 3, 1, and 7?
To determine the number of combinations possible using the numbers 9, 3, 1, and 7, we can use the concept of permutations. A permutation is an arrangement of objects in a specific order. In this case, we want to find the number of permutations of all the numbers. The formula for permutations of n objects taken r at a time is given by: P(n, r) = n! / (n - r)! Where "!" denotes the factorial function. In this case, we have 4 numbers and we want to arrange all of them, so r = 4. P(4, 4) = 4! / (4 - 4)! = 4! / 0! = 4! / 1 = 4 * 3 * 2 * 1 = 24 Hence, there are 24 different number combinations that can be made using the numbers 9, 3, 1, and 7.
Can you find the prime number combinations of 60?
They are: 2*2*3*5 = 60
How do you find permutation?
If there are n objects and you have to choose r objects then the number of permutations is (n!)/((n-r)!). For circular permutations if you have n objects then the number of circular permutations is (n-1)!
How can you figure out combinations in math?
If you have N things and want to find the number of combinations of R things at a time then the formula is [(Factorial N)] / [(Factorial R) x (Factorial {N-R})]
Find the number of combinations of 10 things taken 6 at a time?
Try 151,600! Permutations & Combinations. P(n,r)=n!(nār)! not P(n,r)=n!/(n!-r!)r! ?
How could you find the number of different combinations of 6 letters in a computer password?
there are 36 different combination possibilities. Try them all.
How can you find the total number of 4-number combinations possible from digits 1-7?
*inclusive: 74 = 2401 *exclusive: 7*6*5*4 = 840
