To determine the number of combinations possible using the numbers 9, 3, 1, and 7, we can use the concept of permutations. A permutation is an arrangement of objects in a specific order. In this case, we want to find the number of permutations of all the numbers.
The formula for permutations of n objects taken r at a time is given by:
P(n, r) = n! / (n - r)!
Where "!" denotes the factorial function.
In this case, we have 4 numbers and we want to arrange all of them, so r = 4.
P(4, 4) = 4! / (4 - 4)!
= 4! / 0!
= 4! / 1
= 4 * 3 * 2 * 1
= 24
Hence, there are 24 different number combinations that can be made using the numbers 9, 3, 1, and 7.
Using the combination fuction, chose three numbers from 45 numbers. The answer is 14,190.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
137, 173, 317, 371, 713, 731 Six combinations can be made.
Their is 25 combinations
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
1000
26 = 64 combinations, including the null combination - which contains no numbers.
Only one.
Assuming that the only permitted operation is addition, then there are 4 combinations.
Assuming you are using the standard English alphabet, the number of combinations you can make are: 26 x 26 = 676 combinations.
Assuming that the six numbers are different, the answer is 15.
35