10x2 - 56 = 88 - 6x2 : 10x2 + 6x2 = 88 + 56 : 16x2 = 144 : x2 = 9 : x = ± 3
3a-6x2
Area 36x4-64x2 and width is 6x2-8x Area = Length * width36x4 -64x2 = L * 6x2 -8x(36x4 -64x2) / (6x2 -8x) = L(36x4 -64x2) / (6x2 -8x) = L((6x2 -8x)2 + 96x3)/ (6x2 -8x) = L1 + 96x3/ (6x2 -8x) = L1 + 96x3/ x(6x -8) = L1 + 96x2/ (6x -8) = L
It is a quadratic expression in x and y. Since it is not an equation it cannot be solved or represent any shape in the 2-dimensional plane.
6x2 + 14x -12 = (3x - 2) (2x + 6). There they are.
If: 15x2-56 = 88+6x2 Then: 9x2 = 144 And: x2 = 16 So: x = 4
This is the equation of a parabola.
10x2 - 56 = 88 - 6x2 : 10x2 + 6x2 = 88 + 56 : 16x2 = 144 : x2 = 9 : x = ± 3
-x(x - 3)(x - 3)
12 4x3=12 6x2=12
In an equation an answer that can be substituted for a variable that makes the equation true. Wich is a answer for any tipe of proumblem (ex. 6x2=12)
In the absence of a proper statement of the equation I can only guess at answers. How about (2x + 3)(3x - 5) which is the factorisation of 6x2 - x - 15 = 0? In which case x = -2/3 or 5/3.
10x2 - 64 = 36 + 6x2; whence, 4x2 - 100 = 0, x2 = 25, and x = ±5.
To find the possible values of x in the equation 6x2 + 7x - 3 = 0, you can try to factor the equation: 6x2 + 7x - 3 = 0 6x2 + 9x - 2x - 3 = 0 3x(2x + 3) - 1(2x + 3) = 0 (3x - 1)(2x + 3) = 0 Now you can solve the individual factors for zero, giving you all potential answers to the problem: 3x - 1 = 0 x = 1/3 2x + 3 = 0 x = -3/2 So the possible values of x are -3/2 and 1/3
the equation 6x^2 - 4x + 25 is a quadratic equation due to the 6x^2 term. Whatever number on the x squared term changes it to a quadratic equation if you were to get rid of the 6x^2 then the equation would simply be -4x+25 making it simply a linear equation. when ever you have an x raised to 2 that term is the quadratic term in the equation.
Im assuming the "6x2" is supposed to be 6x squared. The factored form would be (2x+1) (3x-8)
If that's 6x2, the answer is (2x + 1)(3x - 2)