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Find three consecutive odd integers such that twice the smallest plus three times the largest is equal to the middle integer increased by 6?
Wiki User
∙ 15y ago
The easiest way to solve this is just setting up a few equations.
Three consecutive odd integers are: x, x+2, x+4 where x is some odd integer to be determined.
The constraint is: 2*x+3*(x+4) = (x+2) + 6
Expanding this out we have:
2x + 3x + 12 = x + 8
5x+12 = x + 8
4x = -4
x = -1
So the three integers are -1, 1, and 3.
We can check our work again by putting these integers back into the constraint, just to verify no math mistakes (assuming we are setting up the constraint correctly to begin with).
2*(-1) + 3*(3) = 1 + 6
-2 + 9 = 7
7=7 is correct
Wiki User
∙ 15y ago
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