1x2 1x3 1x4 and so on... 2x3 2x4
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I believe that the numbers One and Nine fit the bill as they would be 1x9= 9 and 1+9=10.
To find the last but one digit in the product of the first 75 even natural numbers, we need to consider the units digit of each number. Since we are multiplying even numbers, the product will end in 0. Therefore, the last but one digit (tens digit) will depend on the multiplication of the tens digits of the numbers. The tens digit will be determined by the pattern of the tens digits of the even numbers being multiplied.
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
The ones digit in even numbers can be any of the following: 0, 2, 4, 6, or 8. This is because even numbers are divisible by 2, meaning they can be expressed as 2 multiplied by another integer. The ones digit is the digit in the ones place of a number, which can range from 0 to 9.
One, two, and three.