Find two numbers whose sum is 64 and whose difference is 12?

Answer 1

Let's denote the two numbers as x and y. From the given conditions, we can write the equations x + y = 64 and x - y = 12. By solving these two equations simultaneously, we can find the values of x and y. Adding the two equations eliminates y, giving 2x = 76, so x = 38. Substituting x back into one of the equations gives y = 26. Therefore, the two numbers are 38 and 26.

Answer 2

Find two numbers if their sum is 64 and their difference is 12.

The two numbers are

Answer 3

64/2=32

32+6=38

32-6=26

26+38=64

38-26=12