Call the unknown number n. From the problem statement, 5(6 + n) = 24, or 30 + 5n = 24, or 5n = 24 - 30 = - 6, or n = -(6/5).
Suppose the number is x. The sum of the number and two is x+2 Four times the sum is 4(x+2) The number times 8 is 8x 24 less than the number times 8 is 8x-24 4(x+2) = 8x-24 4x+8=8x-24 so 4x = 32 and x = 8
24(x + 2.25)
the sum of 18 and a number equals 24
4
To calculate 4 times the sum of a number and 6, you would first find the sum of the number and 6, then multiply that sum by 4. Let's represent the number as 'x'. So, the sum of the number and 6 would be x + 6. Multiplying this sum by 4 gives you the expression 4(x + 6), which simplifies to 4x + 24.
Let the number be x: 5x+x = 24 6x = 24 x = 4
Suppose the number is x. The sum of the number and two is x+2 Four times the sum is 4(x+2) The number times 8 is 8x 24 less than the number times 8 is 8x-24 4(x+2) = 8x-24 4x+8=8x-24 so 4x = 32 and x = 8
24(x + 2.25)
The answer is 24.
-24
the sum of 18 and a number equals 24
4
To calculate 4 times the sum of a number and 6, you would first find the sum of the number and 6, then multiply that sum by 4. Let's represent the number as 'x'. So, the sum of the number and 6 would be x + 6. Multiplying this sum by 4 gives you the expression 4(x + 6), which simplifies to 4x + 24.
24 checking: 120/5=24 24x5=120
130 Degrees180-24=156So you know that the sum of all the angles is 180, so the sum of the other two angles is 156. You Know that angle p is equal to some number x. And you know the angle n is five times some number x or 5x. You know the sum of the two angles numerically and algebraically.6x=156x=26n=5xn=5(26)n=130
29
The sum of the interior angles of a polygon can be calculated using the formula ( (n - 2) \times 180^\circ ), where ( n ) is the number of sides. For a regular 24-gon, ( n = 24 ). Therefore, the sum of the interior angles is ( (24 - 2) \times 180^\circ = 22 \times 180^\circ = 3960^\circ ).