You can put the equation into slope-intercept form and the answer is right there, or you can put it in standard form and make the x coefficient and x "disappear" and solve the equation by dividing the number with y by the number on the other side of the equation.
x=x
you can not solve this equation
27
Set the equation equal to zero. 3x2 - x = -1 3x2 - x + 1 = 0 The equation is quadratic, but can not be factored. Use the quadratic equation.
In its normal form, you do not solve differential equation for x, but for a function of x, usually denoted by y = f(x).
For an equation of the form ax² + bx + c = 0 you can find the values of x that will satisfy the equation using the quadratic equation: x = [-b ± √(b² - 4ac)]/2a
Solve the equation for x, and enter your answer in the box below.
y = x - 7 or, y = 1*x - 7 so that the slope is 1.
The simplest way is to change the subject of the formula so that it is in the form y = mx + c. There are alternatives, but a lot more work. Differentiate the equation equal to x, and solve for dy/dx (that is the slope). Substitute x = 0 in the original equation and solve for y (that is the intercept).
The y-intercept (or y-intercepts) of an equation is where x = 0. Replace x with zero in the equation, and solve for y.The answer depends on what information you are given - and in what form. If the equation of the curve is given in polar coordinates or in parametric form, the process is quite different to that required when given the Cartesian equation.
You can put the equation into slope-intercept form and the answer is right there, or you can put it in standard form and make the x coefficient and x "disappear" and solve the equation by dividing the number with y by the number on the other side of the equation.
You need not have x in an algebraic equation. You solve whichever one is the easiest and that depends on the set of equations that you have.
Set up the equation and solve: x + 5 = -13 (next subtract 5 from each side of the equation to solve for x) x = -18
You are finding the roots or solutions. These are the values of the variable such that the quadratic equation is true. In graphical form, they are the values of the x-coordinates where the graph intersects the x-axis.
The quadratic formula cannot be used to solve an equation if the coefficient of the equation x square term is what?
You would set the equation equal to 0 and then solve for x. You may get one or several answers for x, x being the number(s) that make the equation equal 0.