The factors of 56 are: 1 2 4 7 8 14 28 56 The prime factors are: 2 x 2 x 2 x 7 http://www.classbrain.com/artteach/publish/article_48.shtml?num=56&worksp=
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Well, honey, let me break it down for you. The numbers that divide evenly into 56 are 1, 2, 4, 7, 8, 14, 28, and 56. So, if you're looking to divide 56 without any leftovers, those are the lucky numbers you're gonna wanna play with.
Oh, dude, you just add them up and divide by how many numbers there are. So, like, 51 + 52 + 56 = 159, and since there are three numbers, you divide 159 by 3 and get 53. So, the average is 53.
To get an average, add the numbers together and divide by how many numbers there are.... 33 + 34 + 78 + 56 = 201. 201 / 4 = 50.25
The average of 6, 10, 56, and 104 is 44 6 + 10 + 56 + 104 = 176 there are four numbers, so divide by 4 176 / 4 = 44
add up all of the numbers then divide by how many numbers you have. Ex: 12+56+85+32+32+65+42+41 this equals: 365 now you divide this by 8 because that's how many numbers this problem has. so you divide 365 by 8 and get: 45.6 (approxomatly)