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You find the position-to-value rule for the sequence. This takes the form:
U(n) = a + n*d
where a is a constant [ = U(0), a term calculated by moving BACK one term from the first],
d is the common difference between terms, and
n is the counter or index.
Since both a and d are known, plugging in the value of n gives the nth term.
Beware, though, that some courses teach the rule as
U(n) = a' + d*(n-1) where a' is the first term.
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What is it where you find terms by adding the common difference to the previous terms?
An arithmetic sequence.
How do you find terms in arithmetic sequences?
The following formula generalizes this pattern and can be used to find ANY term in an arithmetic sequence. a'n = a'1+ (n-1)d.
What Find the 90th term of the arithmetic sequence 16,21,26?
The 90th term of the arithmetic sequence is 461
How do you use a arithmetic sequence to find the nth term?
The difference between successive terms in an arithmetic sequence is a constant. Denote this by r. Suppose the first term is a. Then the nth term, of the sequence is given by t(n) = (a-r) + n*r or a + (n-1)*r
What if the second terms of an arithmetic sequence is 5 find the sum of 1st and 3rd term?
sequence 4 5 6 sum =10 sequecnce 0 5 10 sum=10
