You find the position-to-value rule for the sequence. This takes the form:
U(n) = a + n*d
where a is a constant [ = U(0), a term calculated by moving BACK one term from the first],
d is the common difference between terms, and
n is the counter or index.
Since both a and d are known, plugging in the value of n gives the nth term.
Beware, though, that some courses teach the rule as
U(n) = a' + d*(n-1) where a' is the first term.
An arithmetic sequence.
The following formula generalizes this pattern and can be used to find ANY term in an arithmetic sequence. a'n = a'1+ (n-1)d.
The 90th term of the arithmetic sequence is 461
The difference between successive terms in an arithmetic sequence is a constant. Denote this by r. Suppose the first term is a. Then the nth term, of the sequence is given by t(n) = (a-r) + n*r or a + (n-1)*r
sequence 4 5 6 sum =10 sequecnce 0 5 10 sum=10
An arithmetic sequence.
The following formula generalizes this pattern and can be used to find ANY term in an arithmetic sequence. a'n = a'1+ (n-1)d.
The 90th term of the arithmetic sequence is 461
The difference between successive terms in an arithmetic sequence is a constant. Denote this by r. Suppose the first term is a. Then the nth term, of the sequence is given by t(n) = (a-r) + n*r or a + (n-1)*r
sequence 4 5 6 sum =10 sequecnce 0 5 10 sum=10
To find the missing terms in the arithmetic sequence 8, 11, 14, 17, we first identify the common difference. The difference between consecutive terms is 3 (11 - 8 = 3, 14 - 11 = 3, 17 - 14 = 3). Therefore, the terms before 8 can be calculated by subtracting 3: 5 (8 - 3) and 2 (5 - 3). The complete sequence is 2, 5, 8, 11, 14, 17.
i dont get it
27,33,39
It is a sequence of numbers which is called an arithmetic, or linear, sequence.
To find the sum of the first 48 terms of an arithmetic sequence, we can use the formula for the sum of an arithmetic series: Sn = n/2 * (a1 + an), where Sn is the sum of the first n terms, a1 is the first term, and an is the nth term. In this case, a1 = 2, n = 48, and an = 2 + (48-1)*2 = 96. Plugging these values into the formula, we get: S48 = 48/2 * (2 + 96) = 24 * 98 = 2352. Therefore, the sum of the first 48 terms of the given arithmetic sequence is 2352.
Add all the numbers and divide that by the number of numbers.
You divide the head with the tail and do some dancing