Not all numbers are possible and for some numbers there are several solutions. Here are some examples:
0: (5x5)-(5x5)
1: (5:5)+5-5
2: (5:5)+(5:5)
3: (5+5+5):5
4: [(5x5)-5]:5
5: [(5-5)x5]+5
6: [(5x5)+5]:5
7: [(5+5):5]+5
10: 5+5+5-5
11: (5:5)+5+5
15: (5x5)-5-5
20: 5+5+5+5
24: (5x5)-(5:5)
25: (5x5)+5-5
26: (5x5)+(5:5)
30: [(5:5)+5]x5
35: (5x5)+5+5
45: [(5+5)x5]-5
50: (5x5)+(5x5)
55: [(5+5)x5]+5
75: (5+5+5)x5
120: (5x5x5)-5
130: (5x5x5)+5
625: 5x5x5x5
101
8
I'm not entirely sure but maybe it's (5*5)-5+5
it is 1 7 tens 1 fives
Using only sums and differences, and not necessarily all four numbers, 1, 3, 9 and 27 will make all numbers from 0 to 40.
101
5-1/5= 4 4/5 *5 = 24
Two fives and four ones
8
It can be done by: (5*5)-(5/5) = 24
(5/5)5 = 1
hyp~95# 34 £
5*4+3+2
how do i make 17 using only 2 4 6 8
I'm not entirely sure but maybe it's (5*5)-5+5
To make 200 using four numbers between 1-9, you can use the following equation: (9 x 9) + (9 x 9) - (9 + 1) = 200. This equation breaks down to (81) + (81) - (10) = 200. By multiplying two nines together twice and subtracting the sum of 9 and 1, you can achieve the target number of 200.
5 x 5 = 25... 25 + 5 = 30.... 30 / 5 = 6.