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What else can I help you with?
If quartile deviation is 24. find mean deviation and standard deviation?
Information is not sufficient to find mean deviation and standard deviation.
Why we calculate standard deviation and quartile deviation?
we calculate standard deviation to find the avg of the difference of all values from mean.,
Is variance the square root of standard deviation?
No, you have it backwards, the standard deviation is the square root of the variance, so the variance is the standard deviation squared. Usually you find the variance first, as it is the average sum of squares of the distribution, and then find the standard deviation by squaring it.
Suppose the standard deviation is 36 Find the variance?
Variance is 362 or 1296.
How do you use a z table?
A z table is used to calculate the probability of choosing something that is normally distributed. In order to use it, first a z score is needed. A z score is the number of standard distributions a value is away from the mean of the data. In order to find the z score, take the value of the datum, subtract the mean, then divide by the standard deviation. The result is a z score. Look up the z score on the table to find the probability of getting anything equal to or lesser than the value you chose.
How do you find out the z-score?
z-score of a value=(that value minus the mean)/(standard deviation)
How do you find z score are of 0.79?
To get a z-score one needs a standard deviation and a mean as well as the number.
If quartile deviation is 24. find mean deviation and standard deviation?
Information is not sufficient to find mean deviation and standard deviation.
IQ test scores are normally distributed with a mean of 100 and a standard deviation of 15 An individual's IQ score is found to be 110 Find the z-score corresponding to this value?
mean= 100 standard deviation= 15 value or x or n = 110 the formula to find the z-value = (value - mean)/standard deviation so, z = 110-100/15 = .6666666 = .6667
Why we calculate standard deviation and quartile deviation?
we calculate standard deviation to find the avg of the difference of all values from mean.,
Is variance the square root of standard deviation?
No, you have it backwards, the standard deviation is the square root of the variance, so the variance is the standard deviation squared. Usually you find the variance first, as it is the average sum of squares of the distribution, and then find the standard deviation by squaring it.
N equals 36 with a population mean of 74 and a mean score of 79.4 with a standard deviation of 18?
Can someone help me find the answer for a sample n=36 with a population mean of of 76 and a mean of 79.4 with a standard deviation of 18?
What is the z score of 6.56 and how do you find it?
There is insufficient information in the question to answer it. To determine Z-Score, you need raw score, which you gave, but you also need mean and standard deviation, which you did not give. Please restate the question.
How do you find the sample deviation?
You're an idiot. It's standard deviation. Google that for your answer.
How do you find graph median by using standard deviation?
You cannot because the median of a distribution is not related to its standard deviation.
Why would someone need a standard deviation calculator?
A standard deviation calculator allows the user to find the mean spread away from the mean in a statistical environment. Most users needing to find the standard deviation are in the statistics field. Usually, the data set will be given and must be typed into the calculator. The standard deviation calculator will then give the standard deviation of the data. In order to find the variance of the data, simply square the answer.
Which measure would you use to fine the spread of marks in an examination?
The measure commonly used to find the spread of marks in an examination is the standard deviation. It provides a numerical value that indicates how spread out the scores are from the mean score. A larger standard deviation suggests a wider spread of scores, while a smaller standard deviation indicates a more clustered distribution of scores.
