It doesn't. Five 2's = 10.
You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
(22/2+2)x2
Well, honey, if you want to make five 2s equal five, all you gotta do is write it as 2 + 2 + 2/2 = 5. Simple math, darling. Just divide one of those pesky 2s by 2 and voila, you've got yourself a nice little equation that adds up to 5.
Not sure about five, but you can make 42 with 6 2s with this method: 2[(22)! - (2/2) - 2] = 42
(2x2x2)/2 + 2
You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
(22/2+2)x2
2x2x2+2/2 = 9
Well, honey, if you want to make five 2s equal five, all you gotta do is write it as 2 + 2 + 2/2 = 5. Simple math, darling. Just divide one of those pesky 2s by 2 and voila, you've got yourself a nice little equation that adds up to 5.
If 2s = 5 then s = 2.5. So by letting s equal 2.5 (two and one half) you will allow 2s to equal 5.
26
You can use five 2s to make 26 by using the following mathematical expression: ( (2 + 2) \times (2 + 2) + 2 ). This simplifies to ( 4 \times 4 + 2 = 16 + 2 = 18 ), which does not yield 26. Instead, the correct expression would be ( 22 + 2 + 2 ). However, a valid approach is to use ( 22 = 2 \times 10 + 2 ), making it possible to achieve 26 using five 2s.
Not sure about five, but you can make 42 with 6 2s with this method: 2[(22)! - (2/2) - 2] = 42
2s-2b= a+b+c-2b simplified that would be a+c-b.
(2x2x2)/2 + 2
The expression (4s + 2s) can be simplified by combining like terms. When you add the coefficients of (s), you get (6s). Therefore, (4s + 2s = 6s).
2 + 2 * 2(2+2) = 2 + 2 * 24 = 2 + 2 * 16 = 2 + 32 = 34