You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
(22/2+2)x2
2 + 2 + 2 + 2/2 = 6 - 1 = 5
Not sure about five, but you can make 42 with 6 2s with this method: 2[(22)! - (2/2) - 2] = 42
(2x2x2)/2 + 2
You can use three 2s to make 26 as follows (2x2)! + 2 = 26 So you can simply make 26 with five 2s as (2x2!) + 2 - 2 + 2 = 26
(22/2+2)x2
2x2x2+2/2 = 9
2 + 2 + 2 + 2/2 = 6 - 1 = 5
If 2s = 5 then s = 2.5. So by letting s equal 2.5 (two and one half) you will allow 2s to equal 5.
26
Not sure about five, but you can make 42 with 6 2s with this method: 2[(22)! - (2/2) - 2] = 42
2s-2b= a+b+c-2b simplified that would be a+c-b.
(2x2x2)/2 + 2
2 + 2 * 2(2+2) = 2 + 2 * 24 = 2 + 2 * 16 = 2 + 32 = 34
2s-4 equals 2(s-2). You can find the answer by factoring two out of both numbers.
2s + 5 [ge] 49 (ge stands for "greater than or equal to")2s [ge] 44 s [ge] 22 That is, s is greater than or equal to 22.