33 + (3/3)
Each two 3s have different values because they are in different postion
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
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The first three is 3000 and the second three is worth 300.
33 + (3 + 3)/3
102 ÷ 3 = 34
4=4(3s) 4=12s s= 1/3
Each two 3s have different values because they are in different postion
0.1288
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
It could be: 33-(3+3) = 21
5646442324
4s 3p 3s 2p 1s This is probably one of the easiest chemistry problems in the book, you should probably look it up.
The answer depends on which of the two 3s in the number you are referring to!
The 2s orbital and 3s orbital both have the same spherical shape and can hold a maximum of two electrons of opposite spin. They only differ because the 3s orbital is further out from the nucleus than the 2s orbital, thus the 3s orbital has a higher energy value.
The first three is 3000 and the second three is worth 300.
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