It could be: 33-(3+3) = 21
7
4=4(3s) 4=12s s= 1/3
There are: 21/3 = 7
3 * 3 / ( 3 * 3 ) = 1 but that uses only four 3s, so 33 / ( 3 * 3 * 3 ) = 1 uses five 3s
The are two electrons in the 3s orbital of magnesium (Mg.)
33 + (3/3)
There are four 3s in 12. This can be determined by dividing 12 by 3, which equals 4. Each division represents one occurrence of the number 3 within 12.
Is done by (3/3) plus (3/3) = 2
3 + 3 + 3/3 = 7
You can't unless something is missing in your question.
Acc to modern olympic rules, each game is played for 21 points, best of 3s
3s + 1