If y=x+4, then over the domain set (1, 2, 3, 4, 5) the range, or y, would be (5, 6, 7, 8, 9). Whenever x is listed, add 4 to it and write in that value for y.
If 2x + 3y = 4, y= (4 - 2x)/3. In function notation, f(x) = (4 - 2x)/3.
It is DOS-specific function in TurboC to call an interrupt. See the built-in help.
It is a cubic function of y.
Use function mkdir.
If y=x+4, then over the domain set (1, 2, 3, 4, 5) the range, or y, would be (5, 6, 7, 8, 9). Whenever x is listed, add 4 to it and write in that value for y.
No.
I don't think its possible. Every C++ program must at least have the main function.
I believe, you can use C-function - printf().
Using TurboC? kbhit and getch are your friends
int i = 0; while(str[i] != NULL){ i++; }
OS-dependent. Try function 'sleep' in unix or MS-DOS.
By returning a value. Or using type 'void'.
Dynamic binding is achieved via virtual functions and the virtual table that is associated with every class that declares or inherits a virtual function. The virtual table (or v-table) maps every virtual function (including pure-virtual functions) to a function pointer that points to the most-derived overload. This makes it possible to invoke specific behaviour even when the runtime type of the object is unknown to the caller.
go do ya homework
That is not a function, although it does involve the function of addition. A function is something that is done to numbers.
There is no such term as "building function" in C++.