If y=x+4, then over the domain set (1, 2, 3, 4, 5) the range, or y, would be (5, 6, 7, 8, 9). Whenever x is listed, add 4 to it and write in that value for y.
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If 2x + 3y = 4, y= (4 - 2x)/3. In function notation, f(x) = (4 - 2x)/3.
It is DOS-specific function in TurboC to call an interrupt. See the built-in help.
Use function mkdir.
It is a cubic function of y.
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No.
I don't think its possible. Every C++ program must at least have the main function.
Dynamic binding is achieved via virtual functions and the virtual table that is associated with every class that declares or inherits a virtual function. The virtual table (or v-table) maps every virtual function (including pure-virtual functions) to a function pointer that points to the most-derived overload. This makes it possible to invoke specific behaviour even when the runtime type of the object is unknown to the caller.
Using TurboC? kbhit and getch are your friends
By returning a value. Or using type 'void'.
int i = 0; while(str[i] != NULL){ i++; }
OS-dependent. Try function 'sleep' in unix or MS-DOS.
I believe, you can use C-function - printf().
go do ya homework
That is not a function, although it does involve the function of addition. A function is something that is done to numbers.
...a function call.