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How many triangles can you form in a hexagon if you draw all the diagonals from only one vertex?
Either 12,14,16,or18 I think 18. * * * * * The correct answers is 4. You can draw only 3 diagonals from one vertex.
How can you divide a hexagon into 8?
Select any point inside the hexagon and draw a line segment to any point on the boundary of the hexagon. Draw 7 more such segments. These will divide the hexagon into 8 parts. The parts will not be equal but that was not a requirement of the question.
How do you draw the lines to divide rectangle into quarter?
Just draw the diagonals and you have four quarters.
How many diagonals can be drawn from a vertex of an n gon?
n-3 diagonals. Of the n vertices of the polygon, you cannot draw diagonals to the two adjacent vertices since these are sides of the polygon and so not diagonals. And you cannot draw a diagonal from a vertex to itself. So those are three vertices that are ruled out, leaving n-3.
Who many diagonals does a rectangle have?
2 Pentagon-5 Hexagon - 9 formula diagonals=(n-3)+sum from i=1->i=(n-3) [i] diagonals=(n-3)+1+2+. . .+(n-3) The n-3 is because you cannot draw lines to a same point or adjacent ones. The reason (n-3) is used twice, is because the first 2 points you start to draw from are not connected to each other so they draw all the lines they can. Once you get to the third (assuming you are moving in a circle), the number of lines you can draw is reduced by 1, since that line is already drawn (to the first point). The 4th one now already has a line to the first and second points and so draws 2 less lines.
