36
41 + 15 = 36 4 x 9
62.
I usually start from the bottom - is 2 a factor, yes indeed. Then start over. Is 2 a factor, yes. Start over. Is 2 a factor, yes. Is 2 a factor, no. Is 3 a factor, no. is 4 a factor, no. Done.2, 2, 2, 5
The highest common factor of 2 and 4 is 2. The number 2 is a factor of 4.
18x2 + 15x + 2 = (3x + 2)(6x + 1)
2(3x + 1)(3x - 1)
3x(x - 2)(x - 4)
That's a factor string of 36.
(x + 2)(3x - 1)(3x + 1)
-3(x + 2)(x + 4)
36
I'm guessing that's 18x3 + 29x2 + 3x. That factors to x(2x + 3)(9x + 1) 18x3 + 29x2 + 3x factor x = x(18x2 + 29x + 3) write 29x as 27x + 2x = x(18x2 + 27x + 2x + 3) group by two and factor each group = x[(18x2 + 27x) + (2x + 3)] = x[9x(2x + 3) + 1(2x + 3)] continue factoring = x(2x + 3)(9x + 1) Or since (18)(3) = 54 and (27)(2) = 54 then write: = x(18x2 + 29x + 3) = x[(18x + 27)/9][(18x + 2)/2] = x(2x + 3)(9x + 1)
3x3-18x2+24x=3x(x2-6x+8)=3x(x-4)(x-2)
18x2 + 2= 2(9x2 + 1)= 2(9x2 - -1)= 2[(3x)2 - i2]= 2(3x + √-1)(3x - √-1) (substitute i for √-1)= 2(3x + i)(3x - i)
18x2 +12x + 2 this is not a perfect square trinomial so let's work a little bit here. 18x2 +12x + 2 factor 2 = 2(9x2 +6x + 1) = 2(3x + 1)2 represent 2 as (√2)2 = (√2)2(3x + 1)2 = [(√2)(3x + 1)]2 take its square root = (√2)(3x + 1) for all x > -1/3.
x(x - 17)(x - 1)Factorising x3 - 18x2 + 17x:Common factor x of all terms:x(x2 - 18x + 17)17 = -1 x -17, -1 + -17 = -18:x(x - 1)(x - 17)