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What is the factorization of this trinomial 3x3 - 18x2 plus 24x?
3x3-18x2+24x=3x(x2-6x+8)=3x(x-4)(x-2)
How do you factor 16x2 plus 24x plus 9?
factor the trinomial 16x^2+24x+9
Factor y2 plus 5y plus 6?
(y+2)(y+3)
Can you factor 3x 2 plus 13x plus 10?
(x + 1)(3x + 10)
How do you factor 3x2 plus 9x plus 6?
3(x + 1)(x + 2)
What is the factor quadratic of 18x2 plus 15x plus 2?
18x2 + 15x + 2 = (3x + 2)(6x + 1)
Factor 3x3 - 18x2 plus 24x?
3x(x - 2)(x - 4)
Can you factor 9x3 plus 15x2 plus 12x plus 20?
(3x + 5)(3x^2 + 4)
How do you factor -9x3-3x2 plus 3x plus 1?
If that's -9x^3 - 3x^2 + 3x + 1, that factors to (1 - 3x^2)(1 + 3x)
How do you factor 18x2-2?
2(3x + 1)(3x - 1)
How do you factor 18x2 - 2?
2(3x - 1)(3x + 1)
What is the factorization of this trinomial 3x3 - 18x2 plus 24x?
3x3-18x2+24x=3x(x2-6x+8)=3x(x-4)(x-2)
What is the square root of 18x squared plus 12x plus two?
18x2 +12x + 2 this is not a perfect square trinomial so let's work a little bit here. 18x2 +12x + 2 factor 2 = 2(9x2 +6x + 1) = 2(3x + 1)2 represent 2 as (√2)2 = (√2)2(3x + 1)2 = [(√2)(3x + 1)]2 take its square root = (√2)(3x + 1) for all x > -1/3.
How do you factor 18X squared plus 2?
18x2 + 2= 2(9x2 + 1)= 2(9x2 - -1)= 2[(3x)2 - i2]= 2(3x + √-1)(3x - √-1) (substitute i for √-1)= 2(3x + i)(3x - i)
How do you factor -3x2-18x-24?
-3(x + 2)(x + 4)
What is 18x2?
36
How do you factor the trinomial completely 18x3 29x 3x?
I'm guessing that's 18x3 + 29x2 + 3x. That factors to x(2x + 3)(9x + 1) 18x3 + 29x2 + 3x factor x = x(18x2 + 29x + 3) write 29x as 27x + 2x = x(18x2 + 27x + 2x + 3) group by two and factor each group = x[(18x2 + 27x) + (2x + 3)] = x[9x(2x + 3) + 1(2x + 3)] continue factoring = x(2x + 3)(9x + 1) Or since (18)(3) = 54 and (27)(2) = 54 then write: = x(18x2 + 29x + 3) = x[(18x + 27)/9][(18x + 2)/2] = x(2x + 3)(9x + 1)
