It is not factorable because if you do the quadratic formula you get
-6+/- √ 68
__________
4
√ is a square root sign...sorry it doesnt really look like one
quadratic formula
x=-b+/- √ b2-4ac
____________
2a
a=2 b=6 c=-4
No, probably not.
2ay2 + 5ay - 3a = a(2y2 + 5y - 3) = a(2y - 1)(y + 3)
It is a cubic function of y.
88 + 5y - y2 66 - 3y + y2 Subtract: 22 + 8y -2y2
6x^3y^2
2(y - 3)(y - 10)
No, probably not.
5(x + 2y2)(x2 - 2xy2 + 4y4)
2(y^2 + 3y - 2)
12y3 - 30y2 + 12yFactor out a y:y(12y2 - 30y + 12)Factor out a 6:6y(2y2 -5y + 2)Factor 2y2 - 5y + 26y(2y - 1)(y - 2)
2ay2 + 5ay - 3a = a(2y2 + 5y - 3) = a(2y - 1)(y + 3)
It is a cubic function of y.
this equals to 12
The remainder is not zero so y-3 is not a factor of y^4+2y^2-4
(y - 3)(2y + 1)
(2y + 5)(y - 9)
y2 + y2 = 2y2