(2x - 1)(5x + 8)
10x^2 - x - 2 = (5x + 2)(2x - 1)
Factored?2X2 - 2X2X(X - 1)================If this were set to 0, X = 0 and X = 1
(x2-7x+12)/(x2-2x-3)factor the numerator & denominator:(x-4)(x-3)/(x-3)(x-1)now reduce:(x-4)(x-3)/(x+1)(x-3)(x-4)/(x+1)
8x^2 + 6x - 5 = 8x^2 + 10x - 4x - 5 = 2x * (4x + 5) - (4x + 5) = (2x -1) * (4x + 5)
2x(2x - 1)
(2x - 1)(4x + 1)
(2x - 1)(2x + 1)
2x squared - 5x - 3 = (2x +1)(x -3)
9(2x - 1)(2x + 1)
(x - 1)(2x - 9)
(2x-3)(x-1)
There is no rational factorisation.
(2x3 - x2) = x2 (2x - 1)
(2x-1)(2x-1) = 4x^2 -4x + 1
The factors are -1(2x + 1)(3x + 4)
2x squared minus 5x minus 3 factored is (2x+1)(x-3).