You don't. This expression does not have any factors.
-167
-3
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
Factor x3 + x2 + 2x + 2, by grouping. Group the first two terms and the last two terms. Then factor. First, factor x3 + x2 by pulling out an x2 term: x2(x + 1) Second, factor 2x + 2 by pulling out a 2: 2(x + 1) So, you now have: x2(x + 1) + 2(x + 1) If you have factored correctly, the terms inside the parentheses should be the same. Now regroup. ANS: (x + 1)(x2 + 2)
x2 - 4
9 - x2 will factor into (3 - x)(3 + x)
x2-14 does factor but not pretty; it factors to: (x+sqrt14)(x-sqrt14).
x2-3x-28
x2 + 6x - 2 can not be factored
x2(x3 + 1) is the best you can do there.
x2-9x = x(x-9)
x2-x=x(x-1)
x2 - 13 + 30 = x2 + 17, which has no real factors.
x2-6x can be factored into x(x-6). Simply factor out the "x" from both factors.
If you mean "factors", the two monomials have the common factor x2. Divide each factor by x2 to get the other factor.
You can't factor it