-10
6x^2 + 5x + 1 = (3x +1) (2x + 1)
1
1.6667
25x2+30x+9 25*9=225 15*15=225 15+15=3025x2+15x+15x+9[5*5xx 3*5x] [3*5x 3*3]5x(5x+3)+3(5x+3)(5x+3)(5x+3)Answer: (5x+3)2
-5
qwertyuiopasdfjk
(5x + 2)(x + 3)
To factorise the expression (25x + 15y), first identify the greatest common factor (GCF) of the coefficients 25 and 15, which is 5. Then, factor out the GCF from the expression: [ 25x + 15y = 5(5x + 3y) ] So, the factored form is (5(5x + 3y)).
x(x+5)
x2 + 2x - 15 = x2 - 3x + 5x - 15 = x(x - 3) + 5(x - 3) = (x + 5)(x - 3)
6x^2 + 5x + 1 = (3x +1) (2x + 1)
1
(4x-3)(x+2)
25xy+5yz is 5y(5x+z) when factored
Yes and it is 4(5x-7) when factored
5x2 + 9x + 13 has no real factors.
To factorise the expression (5x^{10}), you can identify the common factors. The expression can be factored as (5 \cdot x^{10}). If you are looking to factor it further, you could express (x^{10}) as ((x^5)^2), but the primary factorization remains (5x^{10} = 5 \cdot x^{10}).