a + 99d where 'a' is the first term of the sequence and 'd' is the common difference.
ive been told u hve 2 times sumfin bii sumfin
596
The sequence given is an arithmetic sequence where each term is the sum of the previous term and a constant difference. The constant difference in this sequence is increasing by 1 each time, starting with 2. To find the 100th term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, ( n ) is the term number, and ( d ) is the common difference. Plugging in the values, we get ( a_{100} = 1 + (100-1)2 = 1 + 99*2 = 1 + 198 = 199 ). Therefore, the 100th term in the sequence is 199.
It is 354,224,848,179,261,915,075.
a + 99d where 'a' is the first term of the sequence and 'd' is the common difference.
If the sequence is taken to start 1,1,2,... then the 100th term is 354,224,848,179,261,915,075 And you've got to hope I have typed that in correctly!
If you mean: 34 39 24 ... then the nth term is 39-5n and so the 100th term = -461
"The recursive form is very useful when there aren't too many terms in the sequence. For instance, it would be fairly easy to find the 5th term of a sequence recursively, but the closed form might be better for the 100th term. On the other hand, finding the closed form can be very difficult, depending on the sequence. With computers or graphing calculators, the 100th term can be found quickly recursively."
ive been told u hve 2 times sumfin bii sumfin
596
you replace the "n" with ahundred e.g... if it's 2n+1, you will go 2x100+ 1 which is 201
The sequence given is an arithmetic sequence where each term is the sum of the previous term and a constant difference. The constant difference in this sequence is increasing by 1 each time, starting with 2. To find the 100th term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, ( n ) is the term number, and ( d ) is the common difference. Plugging in the values, we get ( a_{100} = 1 + (100-1)2 = 1 + 99*2 = 1 + 198 = 199 ). Therefore, the 100th term in the sequence is 199.
Well, honey, it looks like we've got ourselves an arithmetic sequence here. Each term is increasing by 6, 8, 10, and 12 respectively. So, if we keep following that pattern, the 100th term would be 6 more than the 99th term, which is 12 more than the 98th term, and so on. Just keep adding 14 to each successive term and you'll eventually get to that 100th term.
It is 354,224,848,179,261,915,075.
what term is formed by multiplying a term in a sequence by a fixed number to find the next term
The 90th term of the arithmetic sequence is 461