Lets say the formula is 5n+6 you would times the 5 by 100 - 500, and then add on the 6! So your answer would be 506.
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a + 99d where 'a' is the first term of the sequence and 'd' is the common difference.
To find the 100th term of the sequence 4, 8, 12, 16, we can observe that each term is increasing by 4. This is an arithmetic sequence with a common difference of 4. The formula to find the nth term of an arithmetic sequence is given by: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. Substituting the values into the formula, we get (a_{100} = 4 + (100-1) \times 4 = 4 + 99 \times 4 = 4 + 396 = 400). Therefore, the 100th term of the sequence is 400.
ive been told u hve 2 times sumfin bii sumfin
Oh, dude, chill out with the math! So, to find the 100th term in that sequence, you just need to figure out the pattern. Looks like each term is increasing by 6, right? So, just do a little math dance and you'll get the 100th term. It's gonna be... 596! Or you could just keep adding 6 to the last term 99 times, but who's got time for that?
The sequence given is an arithmetic sequence where each term is the sum of the previous term and a constant difference. The constant difference in this sequence is increasing by 1 each time, starting with 2. To find the 100th term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, ( n ) is the term number, and ( d ) is the common difference. Plugging in the values, we get ( a_{100} = 1 + (100-1)2 = 1 + 99*2 = 1 + 198 = 199 ). Therefore, the 100th term in the sequence is 199.