gradient = (-2-5) / (2-1) = -7 hence y = -7x + C Since a point on the line is (1,5) 5 = -7 + C from which we have C = 12 The equation is y = 12 - 7x
y=mx+b
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. the equation of a straight line can be found by using two points on a line . First find the gradient of the line using the gradient formula . now substitute the gradient into general form replacing "m" . use one of the points and substitute into equation to solve "c" example 1: find the equation of the line which passes through the points (1,3) and (2,5). step 1: find the gradient M=5-3/2-1=2 (/=divide) step 2: place m into the equation Y=2x+c step 3: substitute point into equation 3=2(1)+c step 4: solve C=1 equation is Y=2x+1 hope that helps :)
The equation of a circle with center (0,2) and radius r is x^2+(y-2)^2=r^2 Since it passes through (0,0) (the origin) 0^2+(0-2)^2=r^2 r^2=4 The equation of the circle is x^2+(y-2)^2=4
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
It is a straight line with no slope with a 'y' intercept of 2
x2-x1/y2-y1 (-3 - 3)/(-3 - (-3)) (-6)/(0) The equation will be y = -6x + 0
y=mx+b
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Well, honey, if you're looking for a function that passes through the points (2, 15) and (3, 26), you're talking about a linear function. The slope of this function would be 11 (rise of 11 over run of 1), so the equation would be y = 11x + b. To find the y-intercept, plug in one of the points, let's say (2, 15), and solve for b. So, the function that passes through those points is y = 11x + 4.
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yes because you will need the slope and y-intercept to find the equation of a line and the point through which the line passes is the y-intercept so it is yes!!!!!!! Good Luck!!!!!!!!!!!!!
y = mx + cWhere m is the gradient of the line and c is a constant (the intercept of the line).The equation of a line is typically written asy=mx+b where m is the slope and b is the y-intercept.If you know two points that a line passes through, this page will show you how to find the equation of the line.