0
What else can I help you with?
The equation below describes a circle. What are the coordinates of the center of the circle (x - 6)2 plus (y plus 5)2 152?
The equation of the circle is given by ((x - 6)^2 + (y + 5)^2 = 152). The general form of a circle's equation is ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. From the equation, the coordinates of the center of the circle are ((6, -5)).
What is the general equation of a circle centered at the origin?
x2 + y2 = r2
What is a line that intercects a circle at one point?
Generally, the equation of a circle is (x-a)2 + (y-b)2 = r2where (a,b) is the centre of a circle, and r is the radius.So you can use this equation along with a general line equation, y=mx+c, or using the gradient and finding the equation of the normal.
What is the formula for the center of the circle?
The formula for the center of a circle is given by the coordinates ((h, k)) in the standard equation of a circle, which is ((x - h)^2 + (y - k)^2 = r^2). Here, ((h, k)) represents the center of the circle, and (r) is the radius. If the equation is presented in a different form, you can derive the center by rearranging the equation to match the standard form.
How do you write an equation in standard form of a circle with a center and radius?
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
How do you find the general form equation of a circle?
There are probably several ways to approach it; one general equation for the circle is: (x - a)2 + (y - b)2 = r2 This describes a circle with center at coordinates (a, b), and with a radius of r.
What is the general form for a line equation?
General form for a line equation is: y=mx+b.
What is the general form of the equation of a circle with center at (a b) and radius of length m?
It is: (x-a)^2 +(y-b)^2 = m squared
The equation below describes a circle. What are the coordinates of the center of the circle (x - 6)2 plus (y plus 5)2 152?
The equation of the circle is given by ((x - 6)^2 + (y + 5)^2 = 152). The general form of a circle's equation is ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. From the equation, the coordinates of the center of the circle are ((6, -5)).
What is the general equation of a circle centered at the origin?
x2 + y2 = r2
If a circle is centered at the origin and the length of its radius is 6 What is the circle's equation?
The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.
What is the general form of the equation of a circle with its center at (-2 1) and passing through (-4 1)?
It is (x + 2)^2 + (y - 1)^2 = 4
What is the general equation of a circle?
Ax2+By2+Bx+Cy+D=0
How do you write the equation of a circle?
The general equation for the circle - or one of them - is: (x - a)^2 + (y - b)^2 = r^2 Where: a and b are the coordinates of the center r is the radius
What is a line that intercects a circle at one point?
Generally, the equation of a circle is (x-a)2 + (y-b)2 = r2where (a,b) is the centre of a circle, and r is the radius.So you can use this equation along with a general line equation, y=mx+c, or using the gradient and finding the equation of the normal.
Which number in the standard equation for a circle centered at the origin should one increase to make the circle larger?
You should increase the radius in the standard equation of a circle centered at the origin. The general form is ( x^2 + y^2 = r^2 ), where ( r ) is the radius. By increasing ( r ), you extend the distance from the center to any point on the circle, making it larger.
What is the standard form of an equation where the poin 3-6 is on a circle whose orgin is the center?
9
