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Since you're doing graphs of linear equations, then you should know by now that
your equation is in a standard form, and you can read straight out of it everything
you need in order to draw the graph.
y = 2x - 2
In this form, the coefficient of 'x' is the slope of the graph, and the constant at the end
is the y-intercept of the graph.
So you can look at it and know immediately the the graph is a straight line,
it has a slope of 2, and it goes through the point [ y = -2 ] on the y-axis.
Assuming the missing symbol there is an equals sign, then we have: y - 2x2 - 4x = 4 We can find it's vertex very easily by solving for y, and finding where it's derivative equals zero: y = 2x2 + 4x + 4 y' = 4x + 4 0 = 4x + 4 x = -1 So the vertex occurs Where x = -1. Now we can plug that back into the original equation to find y: y = 2x2 + 4x + 4 y = 2 - 4 + 4 y = 2 So the vertex is at the point (-1, 2)
No translation will invert a quadratic graph.
y=-10x-4
One point on a logarithmic graph is not sufficient to determine its parameters. It is, therefore, impossible to answer the question.
y = -5