Since you're doing graphs of linear equations, then you should know by now that
your equation is in a standard form, and you can read straight out of it everything
you need in order to draw the graph.
y = 2x - 2
In this form, the coefficient of 'x' is the slope of the graph, and the constant at the end
is the y-intercept of the graph.
So you can look at it and know immediately the the graph is a straight line,
it has a slope of 2, and it goes through the point [ y = -2 ] on the y-axis.
Assuming the missing symbol there is an equals sign, then we have: y - 2x2 - 4x = 4 We can find it's vertex very easily by solving for y, and finding where it's derivative equals zero: y = 2x2 + 4x + 4 y' = 4x + 4 0 = 4x + 4 x = -1 So the vertex occurs Where x = -1. Now we can plug that back into the original equation to find y: y = 2x2 + 4x + 4 y = 2 - 4 + 4 y = 2 So the vertex is at the point (-1, 2)
No translation will invert a quadratic graph.
y=-10x-4
One point on a logarithmic graph is not sufficient to determine its parameters. It is, therefore, impossible to answer the question.
y = -5
zxccvc
-3
no
It is zero.
2x2-6x+2y+18 = 0. Subtract the 2y from both sides. 2x2-6x+18 = -2y. Divide all by -2 to get y by itself. -x2+3x-9 = y. This graph is going to be a parabola that opens downward, like a frown.
3y - 37 = 2x2 - 18x3y = 2x2 - 18x + 37y = (2/3)x2 - 6x + (37/3)The graph is a parabola.Shanice outshines Manuel.
find the constant of variation and the slope of the given line from the graph of y=2.5x
Assuming the missing symbol there is an equals sign, then we have: y - 2x2 - 4x = 4 We can find it's vertex very easily by solving for y, and finding where it's derivative equals zero: y = 2x2 + 4x + 4 y' = 4x + 4 0 = 4x + 4 x = -1 So the vertex occurs Where x = -1. Now we can plug that back into the original equation to find y: y = 2x2 + 4x + 4 y = 2 - 4 + 4 y = 2 So the vertex is at the point (-1, 2)
y=-2x^2+8x+3
No translation will invert a quadratic graph.
No.
y = 2x2 + 3x + 6 Since a > 0 (a = 2, b = 3, c = 6) the graph opens upward. The coordinates of the vertex are (-b/2a, f(-b/2a)) = (- 0.75, 4.875). The equation of the axis of symmetry is x = -0.75.