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[√(4/.4*)]^4 - 4 = [√9]^4 - 4 = 3^4 - 4 = 81 - 4 = 77

N.B. the denominator within the square root is meant to be 0.4 recurring, which is written with a dot above the 4 but I am not able to do this.

0.44444...... = 4/9

Also, if you do (4-40)3 - 4

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Q: How do you make 77 with 4 fours?
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