To get to 21 using 1, 5, 6, and 7, you can calculate (6 + 5) x (1 + 7) = 11 x 8 = 88. This equation follows the order of operations (parentheses first, then multiplication) to achieve the desired result of 88.
6 / (1 - 5/7)
The answer is 6 / (1-5/7). 1- 5/7 = 2/7 6 / (2/7) = 6 * (7/2) = (6*7)/2 = 42/2 = 21. Simples!
9 + 5 + 3 + 3 + 1 + 1 = 21
For this particular problem, you just need to experiment a little. 1 + 2 + 3 + 4 + 5 +6 = 21 (6 integers).
f(n) = (n² + n) / 2 f(1) = (1² + 1) / 2 = 1 f(2) = (2² + 2) / 2 = 3 f(3) = (3² + 3) / 2 = 6 f(4) = (4² + 4) / 2 = 10 f(5) = (5² + 5) / 2 = 15 f(6) = (6² + 6) / 2 = 21
6 / (1 - 5/7)
It can be: (5*6)-21 = 28
How do you add 9, 5, 3, and 1 in such a way to get sum of 21 by using only 6 numbers?You would add 9+5+3+1+1+2 and your answer would be 21.
3*5=15+3+3=21
6+5+5+5
(9+5+5+1+1) x 1
I'm not sure if you are limited by purely addition or what the rules are so I have the following answer:Using only 6 numbers, but any function:3*5-5+9+1+1 = 21
The answer is 6 / (1-5/7). 1- 5/7 = 2/7 6 / (2/7) = 6 * (7/2) = (6*7)/2 = 42/2 = 21. Simples!
3*3*3-(5+(5/5)) 9+3+3+5+1(to the power of 1) ...using 6 numbers logic fullfilled ...here in this answer v use the clause of using all given digits
7-6=1, 1+5=6. 6 is your answer.
5*(7*3 - 6) = 5*(21 - 6) = 5*15 = 75
7/10 - 1/6 = 21/30 - 5/30 = 16/30 = 8/15.7/10 - 1/6 = 21/30 - 5/30 = 16/30 = 8/15.7/10 - 1/6 = 21/30 - 5/30 = 16/30 = 8/15.7/10 - 1/6 = 21/30 - 5/30 = 16/30 = 8/15.