To get to 21 using 1, 5, 6, and 7, you can calculate (6 + 5) x (1 + 7) = 11 x 8 = 88. This equation follows the order of operations (parentheses first, then multiplication) to achieve the desired result of 88.
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6 / (1 - 5/7)
The answer is 6 / (1-5/7). 1- 5/7 = 2/7 6 / (2/7) = 6 * (7/2) = (6*7)/2 = 42/2 = 21. Simples!
9 + 5 + 3 + 3 + 1 + 1 = 21
For this particular problem, you just need to experiment a little. 1 + 2 + 3 + 4 + 5 +6 = 21 (6 integers).
f(n) = (n² + n) / 2 f(1) = (1² + 1) / 2 = 1 f(2) = (2² + 2) / 2 = 3 f(3) = (3² + 3) / 2 = 6 f(4) = (4² + 4) / 2 = 10 f(5) = (5² + 5) / 2 = 15 f(6) = (6² + 6) / 2 = 21