f(n) = (n² + n) / 2
f(1) = (1² + 1) / 2 = 1
f(2) = (2² + 2) / 2 = 3
f(3) = (3² + 3) / 2 = 6
f(4) = (4² + 4) / 2 = 10
f(5) = (5² + 5) / 2 = 15
f(6) = (6² + 6) / 2 = 21
the anser is that you are stupid
A single number, such as 1521273339 does not define a sequence. There is no nth term for a signle number.
1, 3, 6, 10, 15 ,21 The nth term for the sequence (where you replace n with the term you want to find) is: (n(n+1))/2
The nth term of the sequence 2n + 1 is calculated by substituting n with the term number. So, the tenth term would be 2(10) + 1 = 20 + 1 = 21. Therefore, the tenth term of the sequence 2n + 1 is 21.
nth term = 5 +8n
(n^2+n)/2
The sequence 1, 3, 6, 10, 15, 21 consists of triangular numbers, where the nth term can be calculated using the formula ( T_n = \frac{n(n + 1)}{2} ). This formula represents the sum of the first n natural numbers. For example, for n = 1, the term is 1; for n = 2, it is 3, and so on. Thus, the nth term is the sum of the integers from 1 to n.
the anser is that you are stupid
after -9 it is -15 then -21, -27 and the ninth is -36
(1+n) x n/2 or (n + n2)/2
A single number, such as 1521273339 does not define a sequence. There is no nth term for a signle number.
1, 3, 6, 10, 15 ,21 The nth term for the sequence (where you replace n with the term you want to find) is: (n(n+1))/2
The nth term of the sequence 2n + 1 is calculated by substituting n with the term number. So, the tenth term would be 2(10) + 1 = 20 + 1 = 21. Therefore, the tenth term of the sequence 2n + 1 is 21.
nth term = 5 +8n
10n + 1
The nth term for the triangular numbers can be expressed using the formula ( T_n = \frac{n(n + 1)}{2} ), where ( n ) is a positive integer representing the position in the sequence. This formula calculates the sum of the first ( n ) natural numbers, resulting in the sequence 1, 3, 6, 10, 15, 21, and so on. For example, for ( n = 4 ), ( T_4 = \frac{4(4 + 1)}{2} = 10 ).
f = 10n + (n - 1)^2 For n=10 f = 10(10) + (10 - 1)^2 f = 181