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If the sum of the digit is divisible by 3 the number is divisible by?
That means the number itself is divisible by three. the sum of the digits in 144, for example, is 9. 144 divided by 3 is 48. The sum of the digits in 21 is 3. 21 divided by 3 is 7.If the number is an even number and the sum of the digits is divisible by 3, the number is also divisible by 6. 144 is even and the sum of the digits is divisible by 3, so 144 is also divisible by 6. 144/6 = 24. And finally, if the sum is divisible by 9, the number itself is also divisible by 9. 27 is an example of this.
The sum of the digit 65?
The sum of the digits in the number 65 is calculated by adding the individual digits together. In this case, the digits are 6 and 5. Adding 6 + 5 equals 11. Therefore, the sum of the digits in the number 65 is 11.
How many numbers are there whose digits sum to 4?
6
What digit in the ten thousands place is the sum of the digits in 150?
6
What is the sum of 21 equals 3c plus 6?
The solution (not sum) to the equation 21 = 3c + 6 is as follows:21 = 3c + 621 - 6 = 3c + 6 - 615 = 3c3c = 153c/3 = 21/3c = 7
9999555533331111 choose any 6 digits whose addition is equals 21?
3 + 3 + 3 + 1 + 11 = 21
9999555533331111 whose 6 digits sum is 21?
You can't get six odd numbers to add to an odd number in this Universe, so... a little creative thinking (= "cheating") is needed... 3 + 3 + 3 + 1 + 11 uses 6 digits and the sum is 21... ... if you want to be REALLY "creative", turn one of the nines upside down and you could have 6 + 5 + 5 + 3 + 1 + 1...
What is the sum of the digits 6 1 5?
21 is the answer.. dahhh
What 6 digits from the number 9999555533331111 have the sum of 21?
this would be explained on the basis of two FACTS below....... sum of two odd numbers are always even and sum of to even numbers are also always even then how 6 odd numbers (consider 3 pairs, 9 5 3 1 being odd numbers) can make an odd number 21..!! SO SIMPLE Make your basics strong...
The sum of the digits of the number is 6?
the sum of my digits is 6? answer=60
Is 6618 divisible 3 6 and 9?
Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)
9999 5555 3333 1111 from these digits select any 6 digits in such a way that sum of that digit is equal to 21?
5+5+5+1+1+4=21
If the sum of the digit is divisible by 3 the number is divisible by?
That means the number itself is divisible by three. the sum of the digits in 144, for example, is 9. 144 divided by 3 is 48. The sum of the digits in 21 is 3. 21 divided by 3 is 7.If the number is an even number and the sum of the digits is divisible by 3, the number is also divisible by 6. 144 is even and the sum of the digits is divisible by 3, so 144 is also divisible by 6. 144/6 = 24. And finally, if the sum is divisible by 9, the number itself is also divisible by 9. 27 is an example of this.
What is the sum of the digits of 150?
6
Find the sum of the digits in the smallest positive integers that is divisible by 2 and 4 and 6 and 10 and 12 and 14?
The sum of the digits is 6.
There is a number that is 6 times the sum of its digits What is this number?
The number is 54. The sum of its digits is 5 + 4 = 9. 54/9 = 6.
9999555533331111 in this any 6 nos total is 21 what r they?
3*3*3-(5+(5/5)) 9+3+3+5+1(to the power of 1) ...using 6 numbers logic fullfilled ...here in this answer v use the clause of using all given digits
