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You draw a straight line through (0,b) which has a slope of m.

Q: How do you graph an equation written in y equals mx plus b form?

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The graph of is shifted 3 units down and 2 units right. Which equation represents the new graph?

A linear equation has the form of mx + b, while a quadratic equation's form is ax2+bx+c. Also, a linear equation's graph forms a line, while a quadratic equation's graph forms a parabola.

For a straight line graph, if the equation of the graph is written is the slope-intercept form, then the line goes up and to the right when the coefficient of x is positive.

Normally a quadratic equation will graph out into a parabola. The standard form is f(x)=a(x-h)2+k

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no the graph will be written in slope intercept form or y=mx+b

The graph of is shifted 3 units down and 2 units right. Which equation represents the new graph?

The "form" only refers to how the equation of the line is written. It has no effect on what the line looks like when the equation is graphed. To graph a linear equation, no matter what form it's written in: -- Pick a number for 'x'. Use the equation to calculate 'y'. Graph the point. -- Pick another 'x'. Use the equation to calculate the new 'y'. Graph the point. -- Draw a straight line between the two points, and as much farther as you want to in either or both directions.

If a = b then it is a circle; otherwise it is an ellipse.

It gets reflected in the x-axis.

On my graphing calculator, a TI84 Plus, I can enter the equation into the Y= (a button) and then graph it by hitting the Graph button.

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The x intercept is at (84, 0) and the y intercept is at (0, 112) and so with a line join the points together which then will form a graph for the given equation.

The equation contains variables which are only raised to the first power.

It's a non-standard form of the equation for a straight-line graph with a slope of 18 and a y-intercept of 16.

The x intercept is at (84, 0) and the y intercept is at (0, 112) and so with a line join the points together which then will form a graph for the given equation.

It is a horizontal line in the Cartesian plane, or a vertical line in the complex plane. The reason is that these points satisfy the equation while no others do.