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How do you solve 3 to the power of negative 2x plus 2 equals 81?
3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1
How do you write expressions in exponential form of the numbers 3 and 5?
Using the natural (base e) logs, written as "ln", 3 is eln(3) and 5 is eln(5). Or in base 10, 3=10log(3) and 5=10log(5). Check it out by taking log of both sides: log(3) = log(10log(3)) = log(3) x log(10) =log(3) x 1=log(3).
How do you evaluate the expresssion log3 sqrt243?
log(3√243)=log(27√3)
How do you get log 13(7) out of log 13(2) log 13(3) and log 13(5)?
It is not possible.
What is the expression with the logarithm Log 4 plus Log 3?
log4+log3=log(4x3)=log12
What are the army structured self development level 3 module 2 answers?
Good luck...
What are the Army Structured Self-Development Level 3 Module 2 Exam answers?
Good luck...
How many army promotion points for completing SSD level 3?
I think there are 16 promotional points, i am not sure.
If 3 log x - 2 log y?
1
How do you solve 3 to the power of negative 2x plus 2 equals 81?
3^(-2x + 2) = 81? log(3^(-2x + 2)) = log(81) (-2x+2)log(3) = log(81) -2x = log(81)/log(3) - 2 x = (-1/2)(log(81)/log(3)) + 1
What are the 3 types of investigatory project?
1. Structured 2. Semi - structured 3. Unstructured
What is 3x66 as a logarithmic function?
log (3 x 66) = log 3 + log 66
Calculate the decibel change for when an output voltage increases from 2 to 6 v?
Level = 20 times log (6/2) = 20 times log (3) = 9.54 dB
How do you solve log base 2 of x - 3 log base 2 of 5 equals 2 log base 2 of 10?
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5
What is log to the third power equal to?
Log (x^3) = 3 log(x) Log of x to the third power is three times log of x.
How do you write expressions in exponential form of the numbers 3 and 5?
Using the natural (base e) logs, written as "ln", 3 is eln(3) and 5 is eln(5). Or in base 10, 3=10log(3) and 5=10log(5). Check it out by taking log of both sides: log(3) = log(10log(3)) = log(3) x log(10) =log(3) x 1=log(3).
Given log 2 and log 3 how do you compute log 36?
log(36) = 1.5563To solve this problem without using a scientific calculator, factor 36 into 2*2*3*3, and use the formula:log(a*b) = log(a) + log(b)So, in this case:log(36) = log(2) + log(2) + log(3) + log(3) = 0.3010 + 0.3010 + 0.4772 + 0.4772 = 1.5564 (slight rounding error)
