If: 5 = x-y
Then: y = x-5
Find an equation of variation where y varies directly as x. One pair of values is y = 80 when x = 40
zeros values at which an equation equals zero are called roots,solutions, or simply zeros. an x-intercept occurs when y=o ex.) y=x squared - 4 0=(x-2)(x+2) (-infinity,-2)(-2,2) (2,infinity)
that would be limited to 3 and -3 for values of x
That is an impossible equation, because it is stating that m has two values.
There is no property that justifies it. The equation is true for some values of x, not for others.
This is a quadratic equation requiring the values of x to be found. Rearrange the equation in the form of: -3x2-4x+6 = 0 Use the quadratic equation formula to factorise the equation: (-3x+2.69041576)(x+2.23013857) Therefore the values of x are 0.8968052533 or - 2.230138587 An even more accurate answer can be found by using surds instead of decimals.
(52/11, 101/11) and (-2, -11) Rearrange 3x-y = 5 into y = 3x-5 and substitute this into the curve equation and then use the quadratic equation formula to find the values of x which leads to finding the values of y by substituting the values of x into y = 3x-5.
Rearrange the quadratic equation to: x2-6x-9 = 0 and use the quadratic equation formula to find the values of x which are:- x = -1.2426406871 or x = 7.2426406871 When factored: (x+1.2426406871)(x-7.242406871) = 0
There can be no answer. y = y is an identity - a statement that is true for all values of y. That leaves y = - 3 - x. It is not possible to solve one linear equation in two unknown variables (x and y). You can only rearrange the equation: for example, to x+y+3=0.
It is, in fact, an identity - which is an equation which is true for all values of the variable.
They are called the solutions or roots of the equations.
-4
This is a simultaneous equation question. 4x-4y = -40 4x+43 = y Rearrange the second equation so that all the letters and numbers are in line with the first equation remembering to alter the values of the + and - signs. 4x-4y = -40 4x-y = -43 Subtract the second equation from the first equation remembering that a - - is equal to a + This will leave you with -3y = 3 and by dividing both sides by -3 gives you y = -1 Therefore the solution of the simultaneous equation is x = -11 and y = -1. Substitute these values into the original equations to make sure that your solution is correct.
There are no exclude values of the equation, as given.
10.
Find an equation of variation where y varies directly as x. One pair of values is y = 80 when x = 40
It is a quadratic equation and the values of x are: -1/2 and 6