3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
y-3x+6y=12 7y=3x+12 y=3x/7 +12/7
You cannot solve one linear equation in two unknown variables.
3x - 2 = 2x + 4 3x - 2x = 4 + 2 x = 6
Watch closely:6x = 3x + 27Subtract 3x from each side:3x = 27Divide each side by 3:x = 9
23
x=7
x = -8
3
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
-3x + 5 = 20 -3x = 15 x = -5
3x + 2y = 12 ie 2y = 12 - 3x so y = 6 - 3x/2
x = 6
x = -8
7x = 3x - 12 4x=-12 x=-3
x = 5, y = -1
3x + 4= 7 3x= 7-4 3x/3 = 3/3 x=1