oh my god, that was the exact homework i had few days ago, but you have to have a calculator to do this. just plug in the numbers in the but ton Y=, one column you put
-16t squared plus 25t plus 6 then the next column you put 0. the graph should form a parabola.
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Solve this problem -x squared -40x- 80 =0
S=vt-16t2 solve for v is what I will assume you mean. first pull out the t S=t(v-16t) then devide by t S/t=v-16t Then add 16t to both sides S/t + 16t = v This can also be written as (S+16t2)/t = v
formula: h=-16t^2+vt+s H= final height T= time V= velocity S= starting height
d = -(1/2)g*t^2 v = - g*(squareroot(2(d/g))) wrong the real formula is: h=-16t^2+s h= ending height usually 0" t=time s= starting height (example) 0=-16t^2+256 -256 -256 -256=-16t^2 __________ -16 16=t^2 t=4 seconds They're both the same formula, they are just transposed. The ending height is always zero since you want the intermittent distance and time of that distance. d = -(1/2)g*t^2 =-(1/2)(32)*t^2=-16*(t^2)
If the arrow was fired in a direction making an angle x with the horizontal, and assuming that acceleration due to gravity is 32 feet per second^2 ijn the downward direction, then its height at time t iss(t) = 160*sin(x)*t - 16*t^2.