Copied from my answer to your other question:
I have changed your equation from 12x=48 mod 18 to 12x=18 mod 48 as it is impossible to have 48 mod 18 in modular arithmetic/it makes no sense.
Anyway, any modular equation a=b mod m can be rewritten as a-b=km where k is an integer. or in other words, m divides a-b without remainder. Applying this to the equation above we get (12x-18)/48=k. Now just stick it into a calculator and replace x with integers or since 12 is even, a number with + 0.5 until the equation gives out an integer, in this case x turns out to be 1.5, then 5.5, 9.5 etc.
45 30/12 = x/18; 12x = 30 x 18; 12x = 540; x = 540 ÷ 12 = 45
1/9=x/18 18=9x 2=x
4{3x-2}2=36 12x-8=18 12x=26 x=2.16666... I hope I read that equation right. If not, just message me and I can fix it.
3r - 9r = 18 wright equaton -6r = 18 combine like terms r = -3 solve
4x = 72.divide both sides by 4x = 18
6*3-6*2-12x v v 18 - 12-12x v v 6-24x -6 -6 something like that..
45 30/12 = x/18; 12x = 30 x 18; 12x = 540; x = 540 ÷ 12 = 45
i got x = 1.35 12x+18=41-5x +5x 17x+18=41 -18 17x=23 /17 x=1.35
4(3x + 2)-18=14...if this is your problem, the answer is as followsmultiply 4 by everything in parenthesis:12x+8-18=14combine like terms by subtracting 18 from 8:12x-10=14isolate the variable (12x) by adding 10 to each sides:12x=10+1412x=24Divide both sides by 12 to get x by itself:12x/12x=24/12X=2
write it as 2 separate equations: 12x-5y=30 2x-6=30 Now the easiest thing to do is solve the second equation: 2x=36 x=36/2 x=18 Now just plug x=18 into the first equation: 12*18-5y=30 216-5y=30 -5y=-186 y=37.2
x=18
10x + 6 = 12x - 18 Subtract 10x from both sides: 6 = 2x - 18 Add 18 to both sides: 24 = 2x Divide both sides by 2: 12 = x Therefore, x = 12
If that's 12x + 18, that can be factored to 6(2x + 3)
x=18
Solve, using the Rule of 72 rate = 4%, years = 18, fv=$8,000. Solve for PV. Formula: PV = $1/(1+r) t PV = $8000/(1+.04) 18 PV = $8000/2.0258 3949.03 = $8000/2.20258
U can subtract 18 from each side of the equation.
25-7=18 18/3=6