3r - 9r = 18 wright equaton
-6r = 18 combine like terms
r = -3 solve
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(3r + 18)/12 = (4r - 48)/4Multiply both sides by 12: (3r + 18) = 3*(4r - 48)or: 3r + 18 = 12r - 144Subtract 3r from both sides: 18 = 9r - 144Add 144 to both sides: 162 = 9rDivide both sides by 9: 18 = rAnswer: r = 18
Cant do much with this one.9r-4s / 9r+6s9r-4s / 3(3r+2s)
To answer a quadratic like this, st everything equal to zero. 5r^2+12r=-4r^2-4 9r^2+12r+4=0 Ask yourself what two numbers add to get 12 that multiply to get 9*4=36 1*36 no 2*18 no 3*12 no 4*9 no 6*6 yes (3r+2)(3r+2) The first and last multiply to get 6 and the outside and inside multiply to get 6. That's (3r+)^2
-9r = 20 + rsubtract r from both sides-10r = 20divide both sides by -10r = -2
3(3r-5s = -16) 5(5r+3s = 64) Multiply all terms in the first equation by 3 and in the second equation by 5: 9r-15s = -48 25r+15s = 320 Add the equations together in order to eliminate s: 34r = 272 Divide both sides by 34 to find the value of r: r = 8 Substitute the value of r into the original equations to find the value of s: Therefore: r = 8 and s = 8