(3r + 18)/12 = (4r - 48)/4Multiply both sides by 12: (3r + 18) = 3*(4r - 48)or: 3r + 18 = 12r - 144Subtract 3r from both sides: 18 = 9r - 144Add 144 to both sides: 162 = 9rDivide both sides by 9: 18 = rAnswer: r = 18
Cant do much with this one.9r-4s / 9r+6s9r-4s / 3(3r+2s)
To answer a quadratic like this, st everything equal to zero. 5r^2+12r=-4r^2-4 9r^2+12r+4=0 Ask yourself what two numbers add to get 12 that multiply to get 9*4=36 1*36 no 2*18 no 3*12 no 4*9 no 6*6 yes (3r+2)(3r+2) The first and last multiply to get 6 and the outside and inside multiply to get 6. That's (3r+)^2
-9r = 20 + rsubtract r from both sides-10r = 20divide both sides by -10r = -2
3(3r-5s = -16) 5(5r+3s = 64) Multiply all terms in the first equation by 3 and in the second equation by 5: 9r-15s = -48 25r+15s = 320 Add the equations together in order to eliminate s: 34r = 272 Divide both sides by 34 to find the value of r: r = 8 Substitute the value of r into the original equations to find the value of s: Therefore: r = 8 and s = 8
9r = 3r + 6 subtract 3r from both sides 6r = 6 divide both sides by 6 r=1 ■
9r = 3r+6 Subtract 3r from both sides: 6r = 6 Divide both sides by 6 to find the value of r: r = 1
(3r + 18)/12 = (4r - 48)/4Multiply both sides by 12: (3r + 18) = 3*(4r - 48)or: 3r + 18 = 12r - 144Subtract 3r from both sides: 18 = 9r - 144Add 144 to both sides: 162 = 9rDivide both sides by 9: 18 = rAnswer: r = 18
Cant do much with this one.9r-4s / 9r+6s9r-4s / 3(3r+2s)
(3r - 2)(3r - 2) or (3r - 2) squared.
9r2-4s2/9r+6sIt looks like you can factors the numerator(3r + 2s)(3r - 2s) [This is the factored form of 9r2-4s2]Put this back into the equation(3r+2s)(3r-2s)/9r+6sYou can also factor the denominator3(3r+2s)Put this back into the equation(3r+2s)(3r-2s)/3(3r+2s)You can cancel out the 3r+2s on top and bottom because they are the same they equal 1. Therefore your final answer is3r-2s over 3You could go further and say this is...r-(2/3)seither one is correct
3(g + 6b + 3r)
(18r - 18) / 2 = (9r - 1)/5 Simplify the left 9r - 9 = (9r - 1)/5 Get rid of fractions by multiplying all by 5 45r - 45 = 9r - 1 Collect terms 36r = 44 Divide r=11/9 ◄ Check: (18 * (11/9) - 18) / 2 = (9 * (11 / 9) - 1) / 5 (22 - 18) / 2 = (11 - 1) / 5 4 / 2 = 10 / 5 2 = 2 ■
To answer a quadratic like this, st everything equal to zero. 5r^2+12r=-4r^2-4 9r^2+12r+4=0 Ask yourself what two numbers add to get 12 that multiply to get 9*4=36 1*36 no 2*18 no 3*12 no 4*9 no 6*6 yes (3r+2)(3r+2) The first and last multiply to get 6 and the outside and inside multiply to get 6. That's (3r+)^2
-2r
-9r = 20 + rsubtract r from both sides-10r = 20divide both sides by -10r = -2
16r2+9r