Subtract 4 from each side: x2 = -4
Trouble! Imaginary numbers...
x =sqrt4 x sqrt -1 ie 2i
This seems a bit upmarket for this board, is there maybe a typo?
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x2 + 6x + 8 = 0 Solve for x.X = -2 or X = -4
A quadratic equation. If you wish to solve for x, you can do so as follows: -x2 + 6x + 7 = 0 x2 - 6x - 7 = 0 (x - 7)(x + 1) = 0 x ∈ {-1, 7}
X2+11x+11 = 7x+9 X2+11x-7x+11-9 = 0 x2+4x+2 = 0 Solve as a quadratic equation by using the quadratic equation formula or by completing the square: x = -2 + or - the square root of 2
I suggest you use the quadratic formula. In this case, a = 1, b = 5, c = 3.
x2 + 10x = 0 x2 + 10x + 25 = 25 (x + 5)2 = 25 x + 5 = +-5 x1 = 0 x2 =10