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Edward Sporer
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∙ 12y agox = (y+2)/(y-3)
Multiply both sides by (y-3): x*(y-3) = y+2
Simplify: xy-3x = y+2
Bring all terms containing y to one side and all those not containing y to the other side by adding or subtracting suitable numbers to both sides of the equation
add 3x: xy = 3x+y+2
subtract y: xy-y = 3x+2
factorise left hand side: y(x-1) = 3x+2
divide both sides by x-1: y = (3x+2)/(x-1)
You can only carry out the last step, division by x-1, when x is not 1. For if x=1 then x-1 is zero and division by zero is not defined.
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Can you solve y3 125?
No, because it is not an equation (or inequality), but simply two expressions separated by a space.
What problems make the answer 38?
OK< SO< there are many problems that make the answer 38. A few examples:p-36= 74 where "p" equals 38.x+(-19) = 19 where "x" equals 38.i + 5783 = 5821 where "i" equals 38.94 - 56 - x where "x" equals 38.h +3 = 41 where "h" is equal to 38.y3 +19 = 54891 where "y3" equals 54872 where plain "y" would equal 38 (38x38x38 = 54872).And you could come up with a tON more, but that is some possible ones.
How do you simplify 10xy3 times 8x5y3?
10xy3 * 8x5y3 = (10*8)*(x*x5)*(y3*y3) = 80x6y6
What is Y3( and times-1)?
4
Can you solve for a b and c in the quadratic equation with only a list of data points?
Yes. You need at least three points with x and y coordinates for this. Let the points be: A(x1, y1), B(x2, y2) and C(x3, y3). For each of the points yi = ax2i + bxi + c, so you have to solve a set of simultaneous equations for i=1 ... 3(the y's and x's are no longer variables! the a, b, c are!): y1 = ax21 + bx1 + c, y2 = ax22 + bx2 + c, y3 = ax23 + bx3 + c
How do you solve y to the 3 plus 9y plus 10y-5 divided by y plus 2?
y3 + 9y + 10y - 5/y + 2 can not be solved, as it is not an equation. If you would like to simplify it, you can reduce it a bit: = y3+ 19y - 5/y + 2
How to solve Y3 - 7500y - 125000 equals 0?
Lets start by putting the known number on the other side. Y3 -7500y=125000. There is your start. Take it from here.
Iy y equals 3 then y3 y3-y equals?
72
What is the coefficient of -y3 plus 7y3?
-y3 + 7y3
What is the solution to x3 plus 1331 equals y3?
One equation with two unknowns usually does not have a solution.
What is the answer of x2 plus y3 plus 15?
X2+Y3+15 All you can do is simplify it.
X4 plus y4 divided by x plus y?
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
Is the y3 equals x is linear function?
no
If y equals 3 then y3 y3-y equals?
y3 x y3 - y (3)3 x 3(3) - 3 9 x 9 - 3 = ? 9 x 9= 81 81 - 3 = 78 I hope that solves your problem
Whats y3+x3+z3 equals to?
3xyz
What x3 plus y3 called?
It is an algebraic expression.
Is y-1 is a factor of y3-19y plus 30?
No.
